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In: Statistics and Probability

9% of all Americans live in poverty. If 46 Americans are randomly selected, find the probability...

9% of all Americans live in poverty. If 46 Americans are randomly selected, find the probability that

a. Exactly 3 of them live in poverty.
b. At most 1 of them live in poverty.
c. At least 45 of them live in poverty

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orchestra answered 1 year ago
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