Question

In: Statistics and Probability

18% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability...

18% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability that

a. Exactly 8 of them live in poverty.  
b. At most 11 of them live in poverty.   
c. At least 6 of them live in poverty.   
d. Between 5 and 9 (including 5 and 9) of them live in poverty.

Solutions

Expert Solution


Related Solutions

18% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability...
18% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability that a. Exactly 9 of them major in STEM.   b. At most 12 of them major in STEM.   c. At least 8 of them major in STEM.   d. Between 9 and 13 (including 9 and 13) of them major in STEM.
8% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability...
8% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability that a. Exactly 1 of them live in poverty.   ____ b. At most 5 of them live in poverty. ____   c. At least 4 of them live in poverty.   ____ d. Between 1 and 7 (including 1 and 7) of them live in poverty.  ____
18% of all Americans live in poverty. If 43 Americans are randomly selected, find the probability...
18% of all Americans live in poverty. If 43 Americans are randomly selected, find the probability that a. Exactly 8 of them live in poverty. b. At most 9 of them live in poverty. c. At least 8 of them live in poverty. d. Between 4 and 10 (including 4 and 10) of them live in poverty.
13% of all Americans live in poverty. If 45 Americans are randomly selected, find the probability that
13% of all Americans live in poverty. If 45 Americans are randomly selected, find the probability that A. Exactly 5 of them live in poverty.                            [ Select ]                       ["0.46", "0.17", "0.83", "0.05"]       B. At most 5 of them live in poverty.                            [ Select ]                       ["0.46", "0.83", "0.17", "0.54"]...
8% of all Americans live in poverty. If 43 Americans are randomly selected, find the probability...
8% of all Americans live in poverty. If 43 Americans are randomly selected, find the probability that a. Exactly 5 of them live in poverty. b. At most 1 of them live in poverty. c. At least 42 of them live in poverty.
14% of all Americans live in poverty. If 46 Americans are randomly selected, find the probability...
14% of all Americans live in poverty. If 46 Americans are randomly selected, find the probability that A. Exactly 7 of them live in poverty. B. At most 6 of them live in poverty. C. At least 4 of them live in poverty. D. Between 4 and 8 (including 4 and 8) of them live in poverty.
9% of all Americans live in poverty. If 46 Americans are randomly selected, find the probability...
9% of all Americans live in poverty. If 46 Americans are randomly selected, find the probability that a. Exactly 3 of them live in poverty. b. At most 1 of them live in poverty. c. At least 45 of them live in poverty
62% of all Americans are home owners. If 44 Americans are randomly selected, find the probability...
62% of all Americans are home owners. If 44 Americans are randomly selected, find the probability that a. Exactly 25 of them are are home owners.  ____ b. At most 26 of them are are home owners. ___ c. At least 28 of them are home owners.  _____ d. Between 24 and 28 (including 24 and 28) of them are home owners.  ___
66% of all Americans are homeowners. If 40 Americans are randomly selected, find the probability that...
66% of all Americans are homeowners. If 40 Americans are randomly selected, find the probability that a. Exactly 27 of them are homeowners. b. At most 25 of them are homeowners. c. At least 24 of them are homeowners. d. Between 24 and 29 (including 24 and 29) of them are homeowners.
66% of all Americans are homeowners. If 39 Americans are randomly selected, find the probability that:...
66% of all Americans are homeowners. If 39 Americans are randomly selected, find the probability that: C. At least 27 of them are homeowners. How to type this and get the answeron a calculator TI-83 plus.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT