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18% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability...

18% of all Americans live in poverty. If 44 Americans are randomly selected, find the probability that

a. Exactly 8 of them live in poverty.  
b. At most 11 of them live in poverty.   
c. At least 6 of them live in poverty.   
d. Between 5 and 9 (including 5 and 9) of them live in poverty.

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orchestra answered 1 year ago
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