In: Statistics and Probability
a credit card company claims that the mean credit card debt for individuals is greater than 4700.00 you want to test this claim. you find that a random sample of 38 cardholders has a mean credit card balance of 4873.00 and a standard deviation of 575.00 at a=0.05
Given:
Sample size = n = 38
Sample mean = = 4873
Standard deviation = s = 575
Significance level = = 0.05
Claim : A credit card company claims that the mean credit card debt for individuals is greater than 4700.
Hypothesis test :
The null and alternative hypothesis is
Ho : = 4700
Ha : > 4700
Test statistic :
t = ( - ) / s/√n
= (4873 - 4700) / 575 /√38
= 1.855
t = 1.855
Degree of freedom = df = n-1 = 38-1 = 37
P-value :
P-value corresponding to t = 1.855 with df = 37 is
P(t > 1.855) = 0.0358
Since P-value < = 0.05, we reject the null hypothesis.
Dicision : Reject the null hypothesis.
Conclusion : There is sufficient evidence to conclude that a credit card company claims that the mean credit card debt for individuals is greater than 4700 at = 0.05