In: Biology
Sterility is associated with loss of function (LOF) at a gene Z. The gene has 5000 bases where LOF mutations can occur. Assuming the human mutation rate is 2x10^-8 per generation. Homozygotes for LOF alleles at Z are sterile, and heterozygotes have mild sterility issues. The heterozygotes for LOF alleles at Z have 20% fewer children than an average individual I the population, but suffer no other ill effects. A) What is the frequency of the Z allele under mutation-selection balance? B) What proportion of the individuals in the population are sterile due to being homozygous for a LOF mutation at Z?
Loss of function Mutation
It is also called inactivated mutations, result in the gene product having less or no function.
Here the gene Z Has 5000 bases where lof mutations can occur. The human mutation rate is 2 X 10-8 per generation.
Homozygotes for LOF alleles at Z are sterile, that means either it could be dominant or recessive. It carries the same allele. Heterozygotes alleles means that one allele is dominant and one allele is recessive. Now, heterozygotes have mild sterility issues, that means one allele is under mutation and one allele is normal which indicates individual with heterozygotes can carry out generation. In the question above, heterozygotes for LOF alleles at Z have 20% fewer children than an average individual in the population.
Under these conditions, mutation selection balance, i.e., mutation (u) and selection (s) which goes out.
If the Z allele produces 20% less population, that means it can produce 80% of population.
So frequency of Z allele under mutation selection balance is
f = u/s.
With this we can calculate the frequency.
B) individuals in the population carrying homozygotes alleles are sterile if there is maintainencr of the equilibrium. That means, no individual is coming out, and no other individual crying different gene enter the population. If in this population, there is hetrozygote individual,then the probability of being sterile would be 50% in that case only.