A 0.1358-g portion of potassium iodate (MW 214.00), about 2 g of potassium iodide, and 2...

A 0.1358-g portion of potassium iodate (MW 214.00), about 2 g of potassium
iodide, and 2 mL of 6 M hydrochloric acid were dissolved in 25 mL of distilled
water. The triiodide formed during the ensuring reaction was titrated to the
starch end point with 31.94 mL of a thiosulfate solution. A 25.00-mL triiodide
sample solution was titrated to the end point with 21.33 mL of the standardized
thiosulfate solution. Calculate the concentrations of the thiosulfate solution and
the triiodide solution.

Expert Solution

queen_honey_blossom answered 1 year ago

(a) Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (FM 214.00) in a...

(a) Potassium iodate solution was prepared by dissolving 1.022 g of KIO3 (FM 214.00) in a 500 mL volumetric flask. Then 50.00 mL of the solution was pipetted into a flask and treated with excess KI (2 g) and acid (10 mL of 0.5 M H2SO4). How many millimoles of I3− are created by the reaction b) The triiodide from part (a) reacted with 37.57 mL of Na2S2O3 solution. What is the concentration of the Na2S2O3 solution? (c) A 1.223...

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1- In the titration between potassium iodate and the sodium thiosulfate solution, if the titration is...

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