When a solution of potassium iodide is mixed with a solution of lead nitrate, a bright...

When a solution of potassium iodide is mixed with a solution of lead nitrate, a bright yellow solid precipitate forms.
Calculate the mass of the solid produced (molar mass = 461 g/mol) when starting with a solution containing 163.20 g of potassium iodide (molar mass = 166 g/mol), assuming that the reaction goes to completion.
Give your answer to three significant figures.

2KI (aq) + Pb(NO₃)₂ (aq) → PbI₂ (s) + 2KNO₃ (l)

Expert Solution

queen_honey_blossom answered 2 years ago

When a solution of potassium iodide is mixed with a solution of lead nitrate, a bright yellow solid precipitate forms.

When a solution of potassium iodide is mixed with a solution of lead nitrate, a bright yellow solid precipitate forms. Calculate the mass of the solid produced (molar mass = 461 g/mol) when starting with a solution containing 141.00 g of potassium iodide (molar mass = 166 g/mol), assuming that the reaction goes to completion. Give your answer to three significant figures. 2KI (aq) + Pb(NO3)2 (aq) → PbI2 (s) + 2KNO3 (l)

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