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For each strong base solution, determine [OH−] , [H3O+] , pH , and pOH . Part...

For each strong base solution, determine [OH−] , [H3O+] , pH , and pOH .

Part A

0.40 M NaOH , determine [OH−] and [H3O+] .

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Part B

For this solution determine pH and pOH .

Express your answers using two decimal places. Enter your answers numerically separated by a comma.

Part C

2.0×10⁻³ M Ca(OH)2 , determine [OH−] and [H3O+] .

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Part D

For this solution determine pH and pOH .

Express your answers using two decimal places. Enter your answers numerically separated by a comma.

Part E

2.8×10⁻⁴ M Sr(OH)2 , determine [OH−] and [H3O+] .

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Part F

For this solution determine pH and pOH .

Express your answers using two decimal places. Enter your answers numerically separated by a comma.

Part G

9.7×10⁻⁵ M KOH , determine [OH−] and [H3O+] .

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Part H

For this solution determine pH and pOH .

Express your answers using two decimal places. Enter your answers numerically separated by a comma.

Solutions

Expert Solution

Part A and Part B

0.40 M NaOH
[OH-]= 0.40, since it is strong base having OH-
pOH = - log 0.40=0.3979
[H3O+]= Kw/[OH-] = 1.0 x 10^-14 / 0.40= 2.5 x 10^-14
pH = - log [H3O+] = 13.60

Part C and Part D
2 x 10^-3 M Ca(OH)2 - - - > Ca2+ + 2OH-
[OH-]= 2 x (2 x 10^-3) = 4 x 10^-3 M
pOH = - log 4 x 10^-3 =2.397
[H3O+]= 1.0 x 10^-14 / 4 x 10^-3 = 2.5 x 10^-12 M
pH = 11.62

Part E and F
2.8 x 10^-4 M Sr(OH)2 - - - - > Sr2+ + 2OH-
[OH-]= 2 x (2.8 x 10^-4) = 5.6 x 10^-4 M
pOH = - log 5.6 x 10^-4 = 3.252
[H3O+]= 1.0 x 10^-14 / 5.6 x 10^-4 = 1.78 x 10^-11 M
pH = - log 1.78 x 10^-11 = 10.75

Part G and H
9.7 x 10^-5 M KOH
[OH-]= 9.7 x 10^-5 M
pOH = - log 9.7 x 10^-5 =4.013
[H3O+]= 1.0 x 10^-14 / 9.7 x 10^-5 =1.031 x 10^-10 M
pH = - log 1.03 x 10^-10=9.987

queen_honey_blossom answered 1 year ago

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