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For each strong base solution, determine [H3O+], [OH−], pH, and pOH. Part A 8.86×10−3 M LiOH...

For each strong base solution, determine [H3O+], [OH−], pH, and pOH.

Part A 8.86×10−3 M LiOH

Part B 8.86×10−3 M LiOH

Part C 1.14×10−2 M Ba(OH)2

Part D 1.14×10−2 M Ba(OH)2

Part E 2.1×10−4 M KOH

Part F 2.1×10−4 M KOH

Part G 4.8×10−4 M Ca(OH)2

Part H 4.8×10−4 M Ca(OH)2

Solutions

Expert Solution

a)    Assuming 100% dissociation of LiOH

[H3O+]   = 10-14 / [8.86×10−3 ] = 1.128 x 10 -12

[OH−]     = 8.86×10−3                                      

pH,   = -log (1.128 x 10 -12) = 12 - 0.052 = 11.947

pOH = 14 - pH = 14 - 11.947 = 2.053

B)

a)    Assuming 100% dissociation of Ba(OH)2

[H3O+]   = 10-14 / [2x 1.14×10−2] = 4.38 x 10-13

[OH−]     = 2.28 X 10-2                                     

pH,   = -log (4.38 x 10-13) = 13 - 0.64 = 12.3

pOH = 14 - pH = 14 - 12.3 = 1.64

Please post the remaining separately or solve as above...

they are all similar.....

queen_honey_blossom answered 2 years ago
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