In: Statistics and Probability
A normally distributed population has a mean of 74 and a
standard deviation of 14. Determine the probability that a random
sample of size 24 has an average between 71 and 80.
Round to four decimal places.
Solution :
Given that,
mean =
= 74
standard deviation =
= 14
n=24
= 74
=
/
n = 14/
24=2.86
= P(71<
<80 ) = P[(71-74) /2.86 < (
-
) /
< (80-74) / 2.86)]
= P(-1.05 < Z < 2.10)
= P(Z <2.10 ) - P(Z < -1.05)
Using z table,
= 0.9821 -0.1469
probability = 0.8352