In: Statistics and Probability
A normally distributed population has a mean of 425 and a standard deviation of 48
a. Determine the probability that a random sample of size
16
selected from this population will have a sample mean less than
400
b. Determine the probability that a random sample of size
9
selected from the population will have a sample mean greater than or equal to
469
Solution :
Given that,
mean = = 425
standard deviation = = 48
a) n = 16
= = 425
= / n = 48 / 16 = 12
P( < 400) = P(( - ) / < (400 - 425) / 12)
= P(z < -2.08)
Using z table
= 0.0188
b) n = 9
= = 425
= / n = 48 / 9 = 16
P( 469) = 1 - P( 469)
= 1 - P[( - ) / (469 - 425) / 16 ]
= 1 - P(z 2.75)
= 1 - 0.9970
= 0.0030