In: Statistics and Probability
A normally distributed population has a mean of 425 and a standard deviation of 48
a. Determine the probability that a random sample of size
16
selected from this population will have a sample mean less than
400
b. Determine the probability that a random sample of size
9
selected from the population will have a sample mean greater than or equal to
469
Solution :
Given that,
mean =
= 425
standard deviation =
= 48
a) n = 16
=
= 425
=
/
n = 48 /
16 = 12
P( < 400) = P((
-
) /
< (400 - 425) / 12)
= P(z < -2.08)
Using z table
= 0.0188
b) n = 9
=
= 425
=
/
n = 48 /
9 = 16
P(
469) = 1 - P(
469)
= 1 - P[(
-
) /
(469 - 425) / 16 ]
= 1 - P(z
2.75)
= 1 - 0.9970
= 0.0030