In: Statistics and Probability
A normally distributed population has a mean of 425 and a standard deviation of 48
a. Determine the probability that a random sample of size
16
selected from this population will have a sample mean less than
400
b. Determine the probability that a random sample of size
9
selected from the population will have a sample mean greater than or equal to
469
Solution :
Given that,
mean = 
 = 425
standard deviation = 
 = 48
a) n = 16

= 
 = 425

= 
 / 
n = 48 / 
16 = 12
P(
 < 400) = P((
 - 
) / 
< (400 - 425) / 12)
= P(z < -2.08)
Using z table
= 0.0188
b) n = 9

= 
 = 425

= 
 / 
n = 48 / 
9 = 16
P(
469) = 1 - P(
469)
= 1 - P[(
- 
) / 

(469 - 425) / 16 ]
= 1 - P(z 
 2.75)   
= 1 - 0.9970
= 0.0030