In: Statistics and Probability
An audit firm surveyed salespeople cheating on their expense reports and other unethical conduct. In the survey of 200 managers, 58% of the managers have caught salespeople cheating on an expense report, 50% have caught salespeople working a second job on company time, 22% have caught salespeople listing a “bars” as a “restaurants” on an expense report, and 19% have caught salespeople giving a kickback to a customer. What is the estimated upper limit for the proportion of managers who caught salespeople working a second job on company time with a 96% confidence?
sample size n= | 200 | |
sample proportion p̂ =x/n= | 0.5000 | |
std error se= √(p*(1-p)/n) = | 0.0354 | |
for 96 % CI value of z= | 2.054 | |
margin of error E=z*std error = | 0.0726 | |
lower bound=p̂ -E = | 0.4274 | |
Upper bound=p̂ +E = | 0.5726 |
from above:
upper limit for the proportion of managers who caught salespeople working a second job on company time with a 96% confidence =0.5726
(please try 0.572 if z is required to 2 decimals)