In: Statistics and Probability
Suppose that the IQ of adults is normally distributed with a mean of 100 and standard deviation of 15.
(a) What IQ score distinguishes the highest 10%?
(b) What is the probability that a randomly selected person has an IQ score between 91 and 118?
(c) Suppose people with IQ scores above 125 are eligible to join a high-IQ club. Show that approximately 4.78% of people have an IQ score high enough to be admitted to this particular club.
(d) Let X be the number of people in a random sample of 25 who have an IQ score high enough to join the high-IQ club. What probability distribution does X follow? Justify your answer.
(e) Using the probability distribution from part (d), find the probability that at least 2 people in the random sample of 25 have IQ scores high enough to join the high-IQ club. (f) [3 marks] Let L be the amount of time (in minutes) it takes a randomly selected applicant to complete an IQ test. Suppose L follows a uniform distribution from 30 to 60. What is the probability that the applicant will finish the test in less than 45 minutes?
a) P(X > x) = 0.1
Or, P((X - )/ > (x - )/) = 0.1
Or, P(Z > (x - 100)/15) = 0.1
Or, P(Z < (x - 100)/15) = 0.9
Or, (x - 100)/15 = 1.28
Or, x = 1.28 * 15 + 100
Or, x = 119.2
b) P(91 < X < 118)
= P((91 - )/ < (X - )/ < (118 - )/)
= P((91 - 100)/15 < Z < (118 - 100)/15)
= P(-0.6 < Z < 1.2)
= P(Z < 1.2) - P(Z < -0.6)
= 0.8849 - 0.2743
= 0.6106
c) P(X > 125)
= P((X - )/ > (125 - )/)
= P(Z > (125 - 100)/15)
= P(Z > 1.667)
= 1 - P(Z < 1.667)
= 1 - 0.9522
= 0.0478 = 4.78%
d) The probability distribution of X is binomial.
Because, there is n = 25 identical trials.
The probability of success P = 0.0478 remains same for all trials.
Each trial is independent from the other trials.
e) n = 25
P = 0.0478
P(X = x) = nCx * px * (1 - p)n - x
P(X > 2) = 1 - P(X < 2)
= 1 - (P(X = 0) + P(X = 1))
= 1 - (25C0 * (0.0478)^0 * (0.9522)^25 + 25C1 * (0.0478)^1 * (0.9522)^24)
= 1 - 0.6627 = 0.3373
f) P(X < 45) = (45 - 30)/(60 - 30)
= 15/30 = 0.5