The 2018 Canadian internet use survey showed, overall, 94% of Canadians had home internet access, and...

The 2018 Canadian internet use survey showed, overall, 94% of Canadians had home internet access, and about 85% of the internet users bought goods or services online, spending $57.4 billion. Suppose 64 internet users with home internet access were randomly and independently sampled. Find the probability that at least 25% of those sampled currently did not buy goods or services online. Round your answers to the nearest ten-thousandth (4 decimals).

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The 2018 Canadian internet use survey showed, overall, 94% of Canadians had home internet access.

about 85% of the internet users bought goods or services online, spending $57.4 billion.

Suppose 64 internet users with home internet access were randomly and independently sampled.

Find the probability that at least 25% of those sampled currently did not buy goods or services online.

So here we want to find probability of not buying goods online.

P= percentage of users do not buy goods & service online

So P = 1- the percentage of users of buying good online

= 1 - 0.85

= 0.15

P= 0.15

n = 64

x = number of users do not buy goods & service online

x follows binomial with n = 64 & P=0.15

orchestra answered 1 year ago

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