In: Statistics and Probability
The 2018 Canadian internet use survey showed, overall, 94% of Canadians had home internet access, and about 85% of the internet users bought goods or services online, spending $57.4 billion. Suppose 64 internet users with home internet access were randomly and independently sampled. Find the probability that at least 25% of those sampled currently did not buy goods or services online. Round your answers to the nearest ten-thousandth (4 decimals).
The 2018 Canadian internet use survey showed, overall, 94% of Canadians had home internet access.
about 85% of the internet users bought goods or services online, spending $57.4 billion.
Suppose 64 internet users with home internet access were randomly and independently sampled.
Find the probability that at least 25% of those sampled currently did not buy goods or services online.
So here we want to find probability of not buying goods online.
P= percentage of users do not buy goods & service online
So P = 1- the percentage of users of buying good online
= 1 - 0.85
= 0.15
P= 0.15
n = 64
x = number of users do not buy goods & service online
x follows binomial with n = 64 & P=0.15