Question
In: Statistics and Probability
A) In 1997, a survey of 820 households showed that 137 of them use e-mail. Use...
A) In 1997, a survey of 820 households showed that 137 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level. Use this information to answer the following questions.
What is the P-value?
B) In a study of 420,149 cell phone users, 115 subjects developed cancer of the brain or nervous system. Test the claim of a somewhat common belief that such cancers are affected by cell phone use. That is, test the claim that cell phone users develop cancer of the brain or nervous system at a rate that is different from the rate of 0.0340% for people who do not use cell phones. Because this issue has such great importance, use a 0.001 significance level. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
What is the test statistic?
Solutions
orchestra answered 1 year agoRelated Solutions
In? 1997, a survey of 840 households showed that 147 of them use? e-mail. Use those...
In? 1997, a survey of 840 households showed that 147 of them
use? e-mail. Use those sample results to test the claim that more
than? 15% of households use? e-mail. Use a 0.05 significance level.
Use this information to answer the following questions.
a. Which of the following is the hypothesis
test to be? conducted?
b. What is the test? statistic?
c. What is the? P-value?
d. What is the? conclusion?
There is not sufficient evidence to support the claim...
In 1997, a survey of 860 households showed that 161 of them use e-mail. Use those...
In 1997, a survey of 860 households showed that 161 of them
use e-mail. Use those sample results to test the claim that more
than 15% of households use e-mail. Use a 0.05 significance
level.
What is the P-Value?
In 1997, a survey of 840 households showed that 131of them use e-mail. Use those sample...
In 1997, a survey of 840 households showed that 131of them use
e-mail. Use those sample results to test the claim that more than
15% of households use e-mail. Use a 0.05 significance level. Use
this information to answer the following questions.
A survey of 460 workers showed that 154 said it was unethical to monitor employee e-mail....
A survey of 460 workers showed that 154 said it was unethical to
monitor employee e-mail. When 130 senior-level bosses were
surveyed, 4848 said it was unethical to monitor employee e-mail. At
the 1 % significance level, do the data provide sufficient evidence
to conclude that the proportion of workers that say monitoring
employee e-mail is unethical is lessless than the proportion of
bosses? Use the two-proportions z-test to conduct the required
hypothesis test. Let population 1 be workers, and...
A survey of 410 workers showed that 172 said it was unethical to monitor employee e-mail....
A survey of 410 workers showed that 172 said it was unethical to
monitor employee e-mail. When 135 senior-level bosses were
surveyed, 37 said it was unethical to monitor employee e-mail. At
the 1% significance level, do the data provide sufficient evidence
to conclude that the proportion of workers that say monitoring
employee e-mail is unethical is greater than the proportion of
bosses? What is the Parameter of interest? What is the underlying
Distribution?
In a recent survey of 4276 randomly selected households showed that 3549 of them had telephones....
In a recent survey of 4276 randomly selected households showed
that 3549 of them had telephones. Using these results, construct a
99% confidence interval estimate of the true proportion of
households with telephones. Use the PANIC acronym
(2) A survey of households in a small town showed that in 500 of 2,000 sampled...
(2) A survey of households in a small town showed that in 500 of
2,000 sampled households, at least one member attended a town
meeting during the year. What is the 95% confidence interval for
the proportion of households represented at a town meeting?
A national survey of heads of households showed the percentage of those who asked for a...
A national survey of heads of households showed the percentage
of those who asked for a raise and the percentage who got one.
According to the survey, of the women interviewed, 26% had asked
for a raise, and of those women who had asked for a raise, 45%
received the raise. Suppose a woman is randomly selected, then:
(a) Find P (woman did not ask for a raise).
(b) Find P (woman asked for raise and received raise).
You are...
Does it pay to ask for a raise? A national survey of heads of households showed...
Does it pay to ask for a raise? A national survey of heads of
households showed the percentage of those who asked for a raise and
the percentage who got one. According to the survey, of the women
interviewed, 26% had asked for a raise, and of those women who had
asked for a raise, 45% received the raise. If a woman is selected
at random from the survey population of women, find the following
probabilities. (Enter your answers to...
A recent survey of 200 households in the United States showed that 8 had a single...
A recent survey of 200 households in the United States showed
that 8 had a single male as the head of household. A survey of 150
households in Canada showed that 5 had a single male as the head of
household. At α =.05, can it be concluded that the proportion in
the two countries is different?
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