A voltaic cell is constructed from an Ni2+(aq)−Ni(s) half-cell and an Ag+(aq)−Ag(s) half-cell.The initial concentration of...

1. By using data in Table 20.1 in the textbook, calculate the standard emf of this voltaic cell.

Solutions

Expert Solution

Ni(s) --------------> Ni^2+ + 2e^- E0 = 0.23v

2Ag^+(aq)+ 2e^- ----------> 2Ag(s) E0 = 0.80v

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Ni(s) + 2Ag^+(aq) ---------------> 2Ag(s) + Ni^2+ (aq) E0cell = 1.03v

n= 2

Ecell = E0cell -0.0592/n logQ

Ecell = E0cell- 0.0592/2 log[Ni^2+]/[Ag^+]^2

1.13 = 1.03 -0.0296log0.018/[Ag^+]^2

1.13-1.03 = -0.0296log0.018/[Ag^+]^2

-0.1/0.0296 = log0.018/[Ag^+]^2

log0.018/[Ag^+]^2 = -3.3783

0.018/[Ag^+]^2 = 10^-3.3783

0.018/[Ag^+]^2 = 0.0001485

[Ag^+]^2 = 0.018/0.0001485

[Ag^+]^2 = 121.2

[Ag^+] = 11M >>>>>answer

queen_honey_blossom answered 1 year ago

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