In: Biology
Flower color in buffalo clover is either white or some shade of pink to red. Pollen from a red individual was applied to white flowers in 1999. This seed was germinated in 2000 and four red plants were obtained in the progeny. These four red plants were allowed to self pollinate in summer 2000 to produce the next generation. Populations of progeny from each of the four plants were grown in the greenhouse in spring 2001 and the following data were obtained. Propose a hypothesis and calculate a Chi Square for each plant and the pooled data, and determine if these data fit your hypothesis.
Cross Plant Red White
6/2X10/4 #1 21 8
6/2X10/4 #2 53 18
6/2X10/4 #3 49 18
6/2X10/4 #4 60 21
Pooled 183 65
As we can see from the result of F1 cross that ratio of F2 generation population is 3:1:; Red: White
Plant 1 | Observed o | Expected e | Deviation d (Observed- expected) | Deviation square d2 | d2/e |
Red | 21 | 21.75 | -0.75 | 0.5625 | 0.025862 |
White | 8 | 7.25 | 0.75 | 0.5625 | 0.077586 |
Total | 29 | 0.103448 | |||
Plant 2 | Observed o | Expected e | Deviation d (Observed- expected) | Deviation square d2 | d2/e |
Red | 53 | 53.25 | -0.25 | 0.0625 | 0.001174 |
White | 18 | 17.75 | 0.25 | 0.0625 | 0.003521 |
Total | 71 | 0.004695 | |||
Plant3 | Observed o | Expected e | Deviation d (Observed- expected) | Deviation square d2 | d2/e |
Red | 49 | 50.25 | -1.25 | 1.5625 | 0.031095 |
White | 18 | 16.75 | 1.25 | 1.5625 | 0.093284 |
Total | 67 | 0.124378 | |||
Plant 4 | Observed o | Expected e | Deviation d (Observed- expected) | Deviation square d2 | d2/e |
Red | 60 | 60.75 | -0.75 | 0.5625 | 0.009259 |
White | 21 | 20.25 | 0.75 | 0.5625 | 0.027778 |
Total | 81 | 0.037037 | |||
Pool data | Observed o | Expected e | Deviation d (Observed- expected) | Deviation square d2 | d2/e |
Red | 183 | 186 | -3 | 9 | 0.048387 |
White | 65 | 61.5 | 3.5 | 12.25 | 0.199187 |
Total | 248 | 0.247574 | |||
Since there are two alleles which are involved in the cross so the
degree of freedom will be 2-1 = 1.
For df =1 the 5% level of significance, the value is 3.64. which allow us to accept the hypothesis and put data fits in Mendel's monohybrid heterozygous cross.