In: Statistics and Probability
The following data represent the number of people aged 25 to 64 years covered by health insurance (private or government) in 2018. Approximate the mean and standard deviation for age. Age 25-34 35-44 45-54 55-64 Number (millions) 22.3 34.4 35.4 28.9
Solution:
If we make a frequency distribution of age it will be as follows:
Age | frequency (f) |
25 - 34 | 22.3 |
35 - 44 | 34.4 |
45 - 54 | 35.4 |
55 - 64 | 28.9 |
The mean of the grouped frequency distribution is given as follows:
Where, fi's are frequencies and xi's are mid point of the intervals.
Mid-point = (lower limit + upper limit)/2
Age | frequency (fi) | xi | fi xi |
25 - 34 | 22.3 | (25+34)/2 = 29.5 | 657.85 |
35 - 44 | 34.4 | (35+44)/2 = 39.5 | 1358.8 |
45 - 54 | 35.4 | (45+54)/2 = 49.5 | 1752.3 |
55 - 64 | 28.9 | (55+64)/2 = 59.5 | 1719.55 |
Total | 121 | 5488.5 |
From the above table we have,
The mean age is 45.36 years.
For grouped frequency distribution, the standard deviation is given as follows:
Where,
frequency (fi) | xi | fi xi | fi xi2 |
22.3 | (25+34)/2 = 29.5 | 657.85 | 19406.575 |
34.4 | (35+44)/2 = 39.5 | 1358.8 | 53672.6 |
35.4 | (45+54)/2 = 49.5 | 1752.3 | 86738.85 |
28.9 | (55+64)/2 = 59.5 | 1719.55 | 102313.23 |
Total = 121 | Total | 5488.5 | 262131.5 |
From the above table we have,
The standard deviation of age is 10.535 years.
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