Question

In: Statistics and Probability

Age of College Students Find the 80% confidence intervals for the variance and standard deviation of...

Age of College Students Find the 80% confidence intervals for the variance and standard deviation of the ages of seniors at Oak Park College if a random sample of 23 students has a standard deviation of 2.9 years. Assume the variable is normally distributed. Use the chi-square distribution table to find any chi-square values to three decimal places. Round the final answers to one decimal place.

Solutions

Expert Solution

Solution :

Given that,

c = 0.80

s = 2.9

n = 23

At 80% confidence level the is ,

= 1 - 80% = 1 - 0.80 = 0.20

/ 2 = 0.20 / 2 = 0.10

/2,df = 0.10,22 = 30.81

and

1- /2,df = 0.90,22 = 14.04

Point estimate = s2 = 8.41

2L = 2/2,df = 30.81

2R = 21 - /2,df = 14.04

The 80% confidence interval for 2 is,

(n - 1)s2 / 2/2 < 2 < (n - 1)s2 / 21 - /2

( 22 *8.41) / 30.81 < 2 < ( 22 * 8.41) / 14.04

6.0 < 2 < 13.2

(6.0 , 13.2)

The 80% confidence interval for is,

s (n-1) / /2,df < < s (n-1) / 1- /2,df

2.9( 23 - 1 ) / 30.81 < < 2.9 ( 23 - 1 ) / 14.04

2.5 < < 3.6

( 2.5 , 3.6)


Related Solutions

Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for...
Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for those intervals. Show all work. $32,096 $29,716 $29,227 $27,209 $22,794 $19,306 $19,238 $19,164 18,994 $18,329 $17,978 $17,626 $16,823 $16,709 $15,967 $15,921 $15,908 $15,905 $15,638 $15,629 $14,414 $14,229 $14,137 $14,051 $13,907 $13,776 $13,281 $12,739 $12,300 $11,994 $11,262 $11,112 $10,984 $10,824 $10,823 $10,448 $10,081 $9,883 $9,668 $9,663 $9,337 $8,855 $8,741 $8,596 $8,385 $7,204 $7,072 $6,503 $5,653 $4,602
construct the indicated confidence intervals for the population variance and the poplulation standard deviation. assume the...
construct the indicated confidence intervals for the population variance and the poplulation standard deviation. assume the sample is from a normally distributed population. c=0.95, s2=15.40, n=25
Calculate 80%, 90% and 99% confidence intervals for the standard deviation. Include here the sample standard...
Calculate 80%, 90% and 99% confidence intervals for the standard deviation. Include here the sample standard deviation and sample size -30pts- S= n= 〖χ²〗_R=(chi-square right tail)= 〖χ²〗_L=(chi-square left tail)= 80% confidence interval: Interpretation: 〖χ²〗_R= 〖χ²〗_L= 90% confidence interval: Interpretation: 〖χ²〗_R= 〖χ²〗_L= 99% confidence interval: Interpretation: How do these confidence intervals relate to the population standard deviation you calculated in question #1, when the set of data was treated as a population? -5 pts- Use the sample you chose to perform...
Construct 95% confidence intervals for the population variance and population standard deviation of the given values...
Construct 95% confidence intervals for the population variance and population standard deviation of the given values below Sketch the results and interpret your findings (15 points). 1.286   1.138   1.240   1.132   1.381   1.137 1.300   1.167   1.240   1.401   1.241   1.171 1.217   1.360   1.302   1.331   1.383
Calculate 80%, 90% and 99% confidence intervals for the player weight standard deviation. Include here the...
Calculate 80%, 90% and 99% confidence intervals for the player weight standard deviation. Include here the sample standard deviation and sample size -30pts- S= 16.47 n= 50 〖 χ²〗_R=(chi-square right tail)= 〖χ²〗_L=(chi-square left tail)= 80% confidence interval and interpretation: 〖χ²〗_R= 〖χ²〗_L= 90% confidence interval and interpretation: 〖χ²〗_R= 〖χ²〗_L= 99% confidence interval and interpretation: How do these confidence intervals relate to the population standard deviation?
Find the 80% confidence interval for the standard deviation of the ages of seniors at Oak...
Find the 80% confidence interval for the standard deviation of the ages of seniors at Oak Park College if a random sample of 21 students has a standard deviation of 2.3 years. Assume the variable is normally distributed. a.) (1.9,2.9) b.) (2.6, 3.3) c.) (3.7,8.5) d.) (2.6, 7.0)
Find the 80% confidence interval for the standard deviation of the ages of seniors at Oak...
Find the 80% confidence interval for the standard deviation of the ages of seniors at Oak Park College if a random sample of 21 students has a standard deviation of 2.3 years. Assume the variable is normally distributed.
mean 94.6129 n= 31 standard deviation is 45.0612 find the 95% and 99% confidence intervals of...
mean 94.6129 n= 31 standard deviation is 45.0612 find the 95% and 99% confidence intervals of the standard devaition find the 95% and 99% confidence interval for population mean data set 10 19 35 39 41 56 67 67 69 73 75 78 81 82 83 83 84 91 92 94 123 125 137 138 140 142 150 152 161 163 183
Calculate 80%, 90% and 99% confidence intervals for the player weight standard deviation. Sx:17.22429337 and n=40...
Calculate 80%, 90% and 99% confidence intervals for the player weight standard deviation. Sx:17.22429337 and n=40 A) (chi-square right tail)= (chi-square left tail)= 80% confidence interval and interpretation: b) chi-square right tail)= (chi-square left tail)= 90% confidence interval and interpretation: c) chi-square right tail)= (chi-square left tail)= 99% confidence interval and interpretation: d) How do these confidence intervals relate to the population standard deviation?
Determine the mean and standard deviation of your sample. Find the 80%, 95%, and 99% confidence...
Determine the mean and standard deviation of your sample. Find the 80%, 95%, and 99% confidence intervals. Make sure to list the margin of error for the 80%, 95%, and 99% confidence interval. Create your own confidence interval (you cannot use 80%, 95%, and 99%) and make sure to show your work. Make sure to list the margin of error. What trend do you see takes place to the confidence interval as the confidence level rises? Explain mathematically why that...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT