In: Statistics and Probability
Age of College Students Find the 80% confidence intervals for the variance and standard deviation of the ages of seniors at Oak Park College if a random sample of 23 students has a standard deviation of 2.9 years. Assume the variable is normally distributed. Use the chi-square distribution table to find any chi-square values to three decimal places. Round the final answers to one decimal place.
Solution :
Given that,
c = 0.80
s = 2.9
n = 23
At 80% confidence level the
is ,
= 1 - 80% = 1 - 0.80 = 0.20
/ 2 = 0.20 / 2 = 0.10
/2,df =
0.10,22 = 30.81
and
1-
/2,df =
0.90,22 = 14.04
Point estimate = s2 = 8.41
2L
=
2
/2,df
= 30.81
2R
=
21 -
/2,df = 14.04
The 80% confidence interval for
2 is,
(n - 1)s2 /
2
/2
<
2 < (n - 1)s2 /
21 -
/2
( 22 *8.41) / 30.81 <
2 < ( 22 * 8.41) / 14.04
6.0 <
2 < 13.2
(6.0 , 13.2)
The 80% confidence interval for
is,
s
(n-1) /
/2,df <
< s
(n-1) /
1-
/2,df
2.9(
23 - 1 ) / 30.81 <
< 2.9
( 23 - 1 ) / 14.04
2.5 <
< 3.6
( 2.5 , 3.6)