Question

In: Statistics and Probability

A person has 3000 bananas and a camel. The person wants to transport maximum number of...

A person has 3000 bananas and a camel. The person wants to transport maximum number of bananas to a destination which is 1000 KMs away, using only the camel as a mode of transportation. The camel cannot carry more than 1000 bananas at a time and eats a banana every km it travels. What is the maximum number of bananas that can be transferred to the destination using only camel?

Solutions

Expert Solution

Total Banana=3000

1000 bananas per trip

we have to shift to 100km

so camel need to take atleast 3 trips.

so camel have to travel like

starting point is #0

  1. moving from #0 point
  2. return to #0 point
  3. moving from #0 point
  4. return to #0 point
  5. moving from #0 point

Total 5 banana required for each km. and we will shift 2000 to distance first

3000-5d=2000

d=200km

we shift all bananas to 200 km.

Means at 200km point we will have 2000 bananas.

next we need 2 trips from#200 point

  1. moving from #200 point
  2. return to #200point
  3. moving from #200 point

so we required 3 bananas per kms.

we will shift bananas to xkm from 200km. and at the end of xkm we will have 1000 bananas

2000-3d =1000

means d=333.33

so we can take 334km from #200point

So total distance travelled.

334+200 =534kms

balance distance have to travel = 1000-534 =466km.

balance banana = (3000-((200*3)+(334*3)) = 998 bananas

we need to travel 466 km and 998 bananas we have

so remaining bananas when camel reach in destination=998-466=532 banans.

maximum number of bananas can be tranffered to desitination is 532

3000------------->2000 bananas distance travelled 200km

2000------------>998 bananas distance travelled 334km, and total distance travelled =200+334=534kms

998------------->532 bananas, distance travelled 466km, and total distance travelled is =534+466 =1000kms


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