In: Statistics and Probability
Recently, California has pushed for a new ethnic studies graduation requirement for high schoolers and students of the California State University system, AB 331. A sociologist suggests support for the proposed legislation is largely divided by racial groups. The following data table shows support for AB 331 based on the 5 racial groups designated by the U.S. Census. The scale is 1 to 7 where 1 represents no support and 7 represents complete support ----ANOVA method---
White | Black | Asian | Native American or Alaska Native | Native Hawaiian or Pacific Islander |
1 | 5 | 4 | 1 | 5 |
2 | 4 | 2 | 4 | 6 |
7 | 4 | 1 | 2 | 6 |
3 | 4 | 5 | 4 | 7 |
2 | 3 | 4 | 2 | 7 |
treatment | w'hite | Black | Asian | Native American or Alaska Native | Native Hawaiian or Pacific Islander | |||
count, ni = | 5 | 5 | 5 | 5 | 5 | |||
mean , x̅ i = | 3.000 | 4.00 | 3.20 | 2.60 | 6.200 | |||
std. dev., si = | 2.3 | 0.7 | 1.6 | 1.3 | 0.8 | |||
sample variances, si^2 = | 5.500 | 0.500 | 2.700 | 1.800 | 0.700 | |||
total sum | 15 | 20 | 16 | 13 | 31 | 95 | (grand sum) | |
grand mean , x̅̅ = | Σni*x̅i/Σni = | 3.80 | ||||||
( x̅ - x̅̅ )² | 0.640 | 0.040 | 0.360 | 1.440 | 5.760 | |||
TOTAL | ||||||||
SS(between)= SSB = Σn( x̅ - x̅̅)² = | 3.200 | 0.200 | 1.800 | 7.200 | 28.800 | 41.2 | ||
SS(within ) = SSW = Σ(n-1)s² = | 22.000 | 2.000 | 10.800 | 7.200 | 2.800 | 44.8000 |
no. of treatment , k = 5
df between = k-1 = 4
N = Σn = 25
df within = N-k = 20
mean square between groups , MSB = SSB/k-1 =
41.2/4= 10.3000
mean square within groups , MSW = SSW/N-k =
44.8/20= 2.2400
F-stat = MSB/MSW = 10.3/2.24=
4.60
ANOVA | ||||||
SS | df | MS | F | p-value | F-critical | |
Between: | 41.20 | 4 | 10.30 | 4.598 | 0.0085 | 2.8661 |
Within: | 44.80 | 20 | 2.24 | |||
Total: | 86.00 | 24 | ||||
α = | 0.05 |
Decision: p-value<α , reject null
hypothesis
conclusion : there is enough evidence of significant
mean difference among
five treatments