Question

In: Statistics and Probability

Recently, California has pushed for a new ethnic studies graduation requirement for high schoolers and students...

Recently, California has pushed for a new ethnic studies graduation requirement for high schoolers and students of the California State University system, AB 331. A sociologist suggests support for the proposed legislation is largely divided by racial groups. The following data table shows support for AB 331 based on the 5 racial groups designated by the U.S. Census. The scale is 1 to 7 where 1 represents no support and 7 represents complete support ----ANOVA method---

White Black Asian Native American or Alaska Native Native Hawaiian or Pacific Islander
1 5 4 1 5
2 4 2 4 6
7 4 1 2 6
3 4 5 4 7
2 3 4 2 7

Solutions

Expert Solution

treatment w'hite Black Asian Native American or Alaska Native Native Hawaiian or Pacific Islander
count, ni = 5 5 5 5 5
mean , x̅ i = 3.000 4.00 3.20 2.60 6.200
std. dev., si = 2.3 0.7 1.6 1.3 0.8
sample variances, si^2 = 5.500 0.500 2.700 1.800 0.700
total sum 15 20 16 13 31 95 (grand sum)
grand mean , x̅̅ = Σni*x̅i/Σni =   3.80
( x̅ - x̅̅ )² 0.640 0.040 0.360 1.440 5.760
TOTAL
SS(between)= SSB = Σn( x̅ - x̅̅)² = 3.200 0.200 1.800 7.200 28.800 41.2
SS(within ) = SSW = Σ(n-1)s² = 22.000 2.000 10.800 7.200 2.800 44.8000

no. of treatment , k =   5  
df between = k-1 =    4  
N = Σn =   25  
df within = N-k =   20  
      
mean square between groups , MSB = SSB/k-1 =    41.2/4=   10.3000
mean square within groups , MSW = SSW/N-k =    44.8/20=   2.2400
      
F-stat = MSB/MSW =    10.3/2.24=   4.60

ANOVA
SS df MS F p-value F-critical
Between: 41.20 4 10.30 4.598 0.0085 2.8661
Within: 44.80 20 2.24
Total: 86.00 24
α = 0.05

   Decision:   p-value<α , reject null hypothesis
      
conclusion :    there is enough evidence of significant mean difference among five  treatments  


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