The vapour pressure of liquid A at 300 K is 76.7 kPa and that of pure...

The vapour pressure of liquid A at 300 K is 76.7 kPa and that of pure liquid B is 52.0 kPa. These two compounds form ideal liquid and gaseous mixtures. Consider the equilibrium composition of a mixture in which the mole fraction of A in the vapour is 0.350. Calculate the total pressure of the vapour and the composition of the liquid mixture.

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Expert Solution

mole fraction of A = 0.350

mole fraction of B = 1-0.350 = 0.65

Partial pressure of A = mole fraction of A X total pressure

= 0.350 X 128.7

= 45.045 KPa

Partial pressure of B = mole fraction of B X total pressure

= 0.65 X 128.7

= 83.655 KPa

queen_honey_blossom answered 1 year ago

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