Question

Write a program that reads in a single integer.

Display a message depending on what is given:

• When the number is 42, output "42 is the Ultimate Question of Life, the Universe, and Everything."
• When the number is 2020 output "2020 is the current year."
• When the number is greater than 1000 and less than 3000 output "1500 could be a year." where 1500 is the number the user originally inputted
• When none of the above, output "no idea."

One example shown below with the user input highlighted:

Give a number: 2020 2020 is the current year.

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Answer 1

C CODE:

#include <stdio.h>

int main() {
    int num;
    printf("Give a number: ");
    scanf("%d", &num);
    
    if(num == 42)
      printf("%d is the Ultimate Question of Life, the Universe, and Everything.", num);
      
    else if(num == 2020)
      printf("%d is the current year.", num);
      
    else if(num> 1000 && num<3000)
      printf("%d could be a year.", num);
      
    else 
      printf("no idea.");
    return 0;
}

Screenshots: