In: Statistics and Probability
The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 9 in-state applicants results in a SAT scoring mean of 1176 with a standard deviation of 44. A random sample of 16 out-of-state applicants results in a SAT scoring mean of 1105 with a standard deviation of 53. Using this data, find the 98%
confidence interval for the true mean difference between the scoring mean for in-state applicants and out-of-state applicants. Assume that the population variances are not equal and that the two populations are normally distributed.
Step 2 of 3:
Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.
Step 3 of 3: Construct the 98% confidence interval. Round your answers to the nearest whole number.
Solution :
Step 2 :
=> Margin of error E = t*Se
= 2.511*19.765
= 49.629915
Step 3 :
=> The 98% confidence interval is (21.368,120.632)
=> (21,121) (rounded)
Explanation :-