In: Statistics and Probability
The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 88 in-state applicants results in a SAT scoring mean of 1119 with a standard deviation of 57. A random sample of 18 out-of-state applicants results in a SAT scoring mean of 1020 with a standard deviation of 35. Using this data, find the 95% confidence interval for the true mean difference between the scoring mean for in-state applicants and out-of-state applicants. Assume that the population variances are not equal and that the two populations are normally distributed.
Step 1 of 3:
Find the point estimate that should be used in constructing the confidence interval.
Step 2 of 3:
Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.
Step 3 of 3:
Construct the 95% confidence interval. Round your answers to the nearest whole number.
Solution-
Given data,
n1= 88, n2= 18, mean 1=1119 & mean 2 = 1020
Both population is normally distributed.