Complete this table of values for four aqueous solutions at 25

Expert Solution

general: pH = -log c(H+) pOH = -log c(OH-)

c(H+) * c(OH-) = 10^-14

pH + pOH = 14

solution A: c (OH-) = 10^-14 / c(H+) = 5*10^-12

pH = -log (0.002) = 2.7

pOH = 14-2.7 = 11.3

solution B: c (H+) = 10^-14 / c(OH-) = 2.5*10^-10

pH = 9.6

pOH = 4.4

solutionC: c (H+) = 4.6*10^-11

c (OH-) = 2.2*10^-4

pOH = 3.66

solutionD: pH = 10.01

c(H+) = 9.8*10^-11

c(OH-) = 1.0*10^-4

queen_honey_blossom answered 1 year ago

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