In: Chemistry
Design a buffer solution from acids listed in the table.
You need to prepare 1.50 L of buffer with pH 4.30. Show your calculations for molar calculations of acid and conjugate base, then fill in the answer table below.
| 
 Acid  | 
 Formula (H is the acidic hydrogen)  | 
 pKa  | 
| 
 Acetic acid  | 
 CH3CO2H  | 
 4.756  | 
| 
 Benzoic acid  | 
 C6H5CO2H  | 
 4.202  | 
| 
 Formic acid  | 
 HCO2H  | 
 3.745  | 
| 
 Hydrazoic acid  | 
 HN3  | 
 4.600  | 
| 
 Hydrofluoric acid  | 
 HF  | 
 3.170  | 
| 
 Lactic acid  | 
 HC3H5O3  | 
 3.860  | 
| 
 Trifluoroacetic acid  | 
 C2HF3O2H  | 
 2.523  | 
Benzoic acid is chosen, since its pKa is closest to the required pH.
The molar ratio is calculated:
n A- / n HA = 10 ^ (pH - pKa) = 10 ^ (4.30 - 4,202) = 1.25
It has:
i) n A- - 1.25 * n HA = 0
ii) n A- + n HA = M * V = 0.1 M * 1.5 L = 0.15 mol
The system of equations between i and ii is solved:
n A- = 0.083 mol
n HA = 0.067 mol
The mass of benzoic acid and sodium benzoate required is calculated:
m Acid = n HA * MM = 0.067 mol * 122.12 g / mol = 8.18 g
m Benzoate = 0.083 * 144.11 = 11.96 g
The above masses are diluted in a volume of distilled water of 1.5 L.
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