In: Statistics and Probability
An economist is studying the job market in Denver area neighborhoods. Let x represent the total number of jobs in a given neighborhood, and let y represent the number of entry-level jobs in the same neighborhood. A sample of six Denver neighborhoods gave the following information (units in hundreds of jobs).
x | 16 | 32 | 53 | 28 | 50 | 25 |
y | 2 | 2 | 7 | 5 | 9 | 3 |
Complete parts (a) through (e), given Σx = 204, Σy = 28, Σx2 = 7998, Σy2 = 172, Σxy = 1132, and r ≈ 0.859.
(a) Draw a scatter diagram displaying the data.
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(b) Verify the given sums Σx, Σy,
Σx2, Σy2, Σxy, and
the value of the sample correlation coefficient r. (Round
your value for r to three decimal places.)
Σx = | |
Σy = | |
Σx2 = | |
Σy2 = | |
Σxy = | |
r = |
(c) Find x, and y. Then find the equation of the
least-squares line = a + bx. (Round
your answers for x and y to two decimal places.
Round your answers for a and b to three decimal
places.)
x | = | |
y | = | |
= | + x |
(d) Graph the least-squares line. Be sure to plot the point
(x, y) as a point on the line.
(e) Find the value of the coefficient of determination
r2. What percentage of the variation in
y can be explained by the corresponding variation
in x and the least-squares line? What percentage is
unexplained? (Round your answer for r2
to three decimal places. Round your answers for the percentages to
one decimal place.)
r2 = | |
explained | % |
unexplained | % |
(f) For a neighborhood with x = 37 hundred jobs, how many
are predicted to be entry level jobs? (Round your answer to two
decimal places.)
hundred jobs
part a)
Part b)
X | Y | X * Y | X2 | Y2 | |
16 | 2 | 32 | 256 | 4 | |
32 | 2 | 64 | 1024 | 4 | |
53 | 7 | 371 | 2809 | 49 | |
28 | 5 | 140 | 784 | 25 | |
50 | 9 | 450 | 2500 | 81 | |
25 | 3 | 75 | 625 | 9 | |
Total | 204 | 28 | 1132 | 7998 | 172 |
r = 0.859
Part c)
X̅ = Σ( Xi / n ) = 204/6 = 34
Y̅ = Σ( Yi / n ) = 28/6 = 4.67
Equation of regression line is Ŷ = a + bX
b = 0.169
a =( Σ Y - ( b * Σ X) ) / n
a =( 28 - ( 0.1695 * 204 ) ) / 6
a = -1.096
Equation of regression line becomes Ŷ = -1.096 + 0.169 X
part e)
Coefficient of Determination
R2 = r2 = 0.738
Explained variation = 0.738* 100 = 73.8%
Unexplained variation = 1 - 0.738* 100 = 26.2%
part f)
When X = 37
Ŷ = -1.096 + 0.169 X
Ŷ = -1.096 + ( 0.169 * 37 )
Ŷ = 5.16