In: Statistics and Probability
An economist is studying the job market in Denver area neighborhoods. Let x represent the total number of jobs in a given neighborhood, and let y represent the number of entry-level jobs in the same neighborhood. A sample of six Denver neighborhoods gave the following information (units in hundreds of jobs).
x | 14 | 35 | 50 | 28 | 50 | 25 |
y | 1 | 4 | 5 | 5 | 9 | 3 |
1) A. given Σx = 202, Σy = 27, Σx2 = 7830, Σy2 = 157, Σxy = 1069, and r ≈ 0.837.
Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.)
Σx =. | |
Σy = | |
Σx2 = | |
Σy2 = | |
Σxy = | |
r = |
Find x, and y. Then find the equation of the least-squares line = a + bx. (Round your answers for x and y to two decimal places. Round your answers for a and b to three decimal places.)
x | = | |
y | = | |
= | + x |
Find the value of the coefficient of determination r2. What percentage of the variation in y can be explained by the corresponding variation in x and the least-squares line? What percentage is unexplained? (Round your answer for r2 to three decimal places. Round your answers for the percentages to one decimal place.)
r2 = | |
explained | % |
unexplained | % |
(f) For a neighborhood with x = 32 hundred jobs, how many
are predicted to be entry level jobs? (Round your answer to two
decimal places.)
hundred jobs
Computational Table:
X | Y | X^2 | Y^2 | XY | |
14 | 1 | 196 | 1 | 14 | |
35 | 4 | 1225 | 16 | 140 | |
50 | 5 | 2500 | 25 | 250 | |
28 | 5 | 784 | 25 | 140 | |
50 | 9 | 2500 | 81 | 450 | |
25 | 3 | 625 | 9 | 75 | |
Total | 202 | 27 | 7830 | 157 | 1069 |
Correlation coefficient = r :
r = 0.837
Σx = 202. |
Σy = 27 |
Σx2 = 7830 |
Σy2 = 157 |
Σxy = 1069 |
r = 0.837 |
Calculation:
For Slope:
b = 0.155
For Intercept:
a = 4.50 - 0.155*33.67
a = -0.733
Therefore, the least square regression line would be,
= -0.733 + 0.155 (X)
Coefficient of Determination (R2):
R2 = 0.8372 = 0.701
explained = 70.1%
Unexplained = 29.9%
f)
The least square regression line would be,
= -0.733 + 0.155 (X)
For X = 32
= -0.733 + 0.155*32
= 1.60
1.60 hundred jobs