Question

Calculate E∘ for each of the following reactions, and tell which are spontaneous under standard-state conditions. Part A 2Fe2+(aq)+Pb2+(aq)→2Fe3+(aq)+Pb(s) Express your answer using two decimal places. E∘ = V SubmitMy AnswersGive Up Part B Mg(s)+Ni2+(aq)→Mg2+(aq)+Ni(s) Express your answer using two decimal places. E∘ = V SubmitMy AnswersGive Up Part C Tell which are spontaneous under standard-state conditions. Check all that apply. Check all that apply. 2Fe2+(aq)+Pb2+(aq)→2Fe3+(aq)+Pb(s) Mg(s)+Ni2+(aq)→Mg2+(aq)+Ni(s)

Answer 1

2Fe^2+(aq) ---------------> 2Fe^3+9aq0 + 2e^-   E0 = -0.77v

Pb^2+(aq) + 2e^- --------> Pb (s)               E0 = -0.13v

-------------------------------------------------------------------------------

2Fe2+(aq)+Pb2+(aq)→2Fe3+(aq)+Pb(s)    E0 cell =- 0.9v

G^0 = -nE0cell* F

         = -2*-0.9*96500 = 173700v

G^0>0

         it is non spontanous reaction

Mg(s) -----------------> Mg^2+ (aq) + 2e^-      E0 = 2.38v

Ni^2+ + 2e^- --------> Ni(s)                          E0 = -0.23v

------------------------------------------------------------------------

Mg(s)+Ni2+(aq)→Mg2+(aq)+Ni(s)             E0cell = 2.15v

G^0 = -nE0cell* F

               = -2*2.15*96500 = -414950J

G^0<0 spontaneous reaction