In: Statistics and Probability
The following table shows ceremonial ranking and type of pottery sherd for a random sample of 434 sherds at an archaeological location.
Ceremonial Ranking | Cooking Jar Sherds | Decorated Jar Sherds (Noncooking) | Row Total |
A | 90 | 45 | 135 |
B | 89 | 56 | 145 |
C | 76 | 78 | 154 |
Column Total | 255 | 179 | 434 |
Use a chi-square test to determine if ceremonial ranking and pottery type are independent at the 0.05 level of significance.
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: Ceremonial ranking and pottery type are not independent H1: Ceremonial ranking and pottery type are not independent.
H0: Ceremonial ranking and pottery type are independent. H1: Ceremonial ranking and pottery type are not independent.
H0: Ceremonial ranking and pottery type are not independent. H1: Ceremonial ranking and pottery type are independent.
H0: Ceremonial ranking and pottery type are independent. H1: Ceremonial ranking and pottery type are independent.
(b) Find the value of the chi-square statistic for the sample.
(Round the expected frequencies to at least three decimal places.
Round the test statistic to three decimal places.)
Are all the expected frequencies greater than 5?
YesNo
What sampling distribution will you use?
Student's t
chi-square
binomial
normal
uniform
What are the degrees of freedom?
(c) Find or estimate the P-value of the sample test
statistic. (Round your answer to three decimal places.)
p-value > 0.1000
.050 < p-value < 0.100
0.025 < p-value < 0.0500
.010 < p-value < 0.0250
.005 < p-value < 0.010
p-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis of independence?
Since the P-value > α, we fail to reject the null hypothesis.
Since the P-value > α, we reject the null hypothesis.
Since the P-value ≤ α, we reject the null hypothesis.
Since the P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the
application.
At the 5% level of significance, there is sufficient evidence to conclude that ceremonial ranking and pottery type are not independent.
At the 5% level of significance, there is insufficient evidence to conclude that ceremonial ranking and pottery type are not independent.
Solution:
Given:
Observed Frequencies | |||
type of pottery sherd | |||
Ceremonial Ranking | Cooking Jar Sherds | Decorated Jar Sherds (Noncooking) | Row Total |
A | 90 | 45 | 135 |
B | 89 | 56 | 145 |
C | 76 | 78 | 154 |
Column Total | 255 | 179 | 434 |
We have to use a chi-square test to determine if ceremonial ranking and pottery type are independent at the 0.05 level of significance.
Part (a) What is the level of significance?
level of significance = 0.05
State the null and alternate hypotheses.
H0: Ceremonial ranking and pottery type are independent. H1: Ceremonial ranking and pottery type are not independent.
Part b) Find the value of the chi-square statistic for the sample.
Formula for Chi square independence
Where
Oij = Observed frequencies for ith row and jth column.
Eij = Expected frequencies for ith row and jth column.
Where
Thus Expected frequency table is:
Expected Frequencies | ||
type of pottery sherd | ||
Ceremonial Ranking | Cooking Jar Sherds | Decorated Jar Sherds (Noncooking) |
A | 79.320 | 55.680 |
B | 85.196 | 59.804 |
C | 90.484 | 63.516 |
Thus we get:
Oij | Eij | Oij^2/Eij |
90 | 79.320 | 102.118 |
45 | 55.680 | 36.369 |
89 | 85.196 | 92.974 |
56 | 59.804 | 52.438 |
76 | 90.484 | 63.835 |
78 | 63.516 | 95.787 |
Thus
Are all the expected frequencies greater than 5?
Yes.
What sampling distribution will you use?
chi-square
What are the degrees of freedom?
df = ( R - 1) X (C - 1)
R = Number of Rows = 3
C = Number of Columns = 2
thus
df = ( 3- 1 )X ( 2-1)
df = 2 X 1
df = 2
Part c) Find or estimate the P-value of the sample test statistic.
Look in Chi-square table for df = 2 row and find the interval in which fall. then find corresponding right tail area
fall between 9.210 and 10.597
thus p-value is between 0.005 and 0.010
Thus correct answer is:
0.005 < p-value < 0.010
Part (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of independence?
Since 0.005 < p-value < 0.010 that means p-value < 0.05 level of significance.
Thus correct answer is:
Since the P-value ≤ α, we reject the null hypothesis.
Part e) Interpret your conclusion in the context of the application.
At the 5% level of significance, there is sufficient evidence to conclude that ceremonial ranking and pottery type are not independent.