In: Statistics and Probability
The following table shows ceremonial ranking and type of pottery sherd for a random sample of 434 sherds at an archaeological location.
Ceremonial Ranking | Cooking Jar Sherds | Decorated Jar Sherds (Noncooking) | Row Total |
A | 84 | 51 | 135 |
B | 93 | 52 | 145 |
C | 74 | 80 | 154 |
Column Total | 251 | 183 | 434 |
Use a chi-square test to determine if ceremonial ranking and pottery type are independent at the 0.05 level of significance.
(a) What is the level of significance?
State the null and alternate hypotheses.
H0: Ceremonial ranking and pottery type are
not independent.
H1: Ceremonial ranking and pottery type are
independent.
H0: Ceremonial ranking and pottery type are
not independent.
H1: Ceremonial ranking and pottery type are not
independent.
H0: Ceremonial ranking and pottery type are
independent.
H1: Ceremonial ranking and pottery type are not
independent.
H0: Ceremonial ranking and pottery type are
independent.
H1: Ceremonial ranking and pottery type are
independent.
(b) Find the value of the chi-square statistic for the sample.
(Round the expected frequencies to at least three decimal places.
Round the test statistic to three decimal places.)
Are all the expected frequencies greater than 5?
Yes or No
What sampling distribution will you use?
uniform
Student's t
binomialnormal
chi-square
What are the degrees of freedom?
(c) Find or estimate the P-value of the sample test
statistic. (Round your answer to three decimal places.)
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis of independence?
Since the P-value > ?, we fail to reject the null hypothesis.Since the P-value > ?, we reject the null hypothesis.
Since the P-value ? ?, we reject the null hypothesis.Since the P-value ? ?, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the
application.
At the 5% level of significance, there is sufficient evidence to conclude that ceremonial ranking and pottery type are not independent.
At the 5% level of significance, there is insufficient evidence to conclude that ceremonial ranking and pottery type are not independent.
(a) What is the level of significance?
Answer: Significance Level
Null Hypotheis and Alternative Hypothesis
H0: Ceremonial ranking and pottery type are independent.
H1: Ceremonial ranking and pottery type are not independent.
b) The Calculation Table for expected frequencies are :
Obs. Freq | Exp. Freq | |||||
Ceremonial Ranking | Cooking Jar Sherds | Decorated Jar Shreds | Row Total | Cooking Jar Sherds | Decorated Jar Shreds | Row Total |
A | 84 | 51 | 135 | 78.076 | 56.924 | 135 |
B | 93 | 52 | 145 | 83.859 | 61.141 | 145 |
C | 74 | 80 | 154 | 89.065 | 64.935 | 154 |
Column Total | 251 | 183 | 434 | 251 | 183 | 434 |
Are all the expected frequencies greater than 5?
Answer: Yes
What sampling distribution will you use?
Answer: chi-square
What are the degrees of freedom?
Answer: (r-1)*(c-1) = (3-1)*(2-1) = 2*1 =2
The Calculation For Chi square test statistic is
Obs. Freq ( f) |
Exp. Freq ( e) |
(f-e)2/e | |
84 | 78.076 | 0.449 | |
51 | 56.924 | 0.617 | |
93 | 83.859 | 0.996 | |
52 | 61.141 | 1.367 | |
74 | 89.065 | 2.548 | |
80 | 64.935 | 3.495 | |
Total | 434 | 434 | 9.472 |
Under Ho, the test statistic is
c) The P-Value is 0.009
d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of independence?
Answer: Since the P-value ? ?, we reject the null hypothesis
e) Interpret your conclusion in the context of the application.
Answer: At the 5% level of significance, there is sufficient evidence to conclude that ceremonial ranking and pottery type are not independent.