In: Economics
Cash flow series
Annual Cash Flow ($ per year) | Annual Cash Flow ($ per year) | Annual Cash Flow ($ per year) | |
Year | Prob = 0.3 | Prob = 0.22 | Prob = 0.48 |
0 | –5000 | –6000 | –4000 |
1 | 1000 | 500 | 3100 |
2 | 1000 | 1500 | 1200 |
3 | 1000 | 2000 | 100 |
Determine the expected present worth of the following cash flow series if each series may be realized with the probability shown at the head of each column. Let i = 20% per year.
The present worth when the probability is 0.3 is $
The present worth when the probability is 0.22 is $
The present worth when the probability is 0.48 is $
The expected present worth value is $ .
a)
Let us take the case, when probability=0.30
Initial Cash flow-Co=-$5000
Cash flow in year 1=CF1=$1000
Cash flow in year 2=CF2=$1000
Cash flow in year 3=CF3=$1000
Interest rate=i=20%
PW (p=0.30)=-Co+CF1*(P/F,20%,1)+CF2*(P/F,20%,2)+CF3*(P/F,20%,3)
Let us calculate interest factors
(P/F,20%,1)=1/(1+20%)^1=0.833333
(P/F,20%,2)=1/(1+20%)^2=0.694444
(P/F,20%,3)=1/(1+20%)^3=0.578704
PW (p=0.30)=-5000+1000*0.833333+1000*0.694444+1000*0.578704=-$2893.52
b)
Let us take the case, when probability=0.22
Initial Cash flow-Co=-$6000
Cash flow in year 1=CF1=$500
Cash flow in year 2=CF2=$1500
Cash flow in year 3=CF3=$2000
Interest rate=i=20%
PW (p=0.22)=-Co+CF1*(P/F,20%,1)+CF2*(P/F,20%,2)+CF3*(P/F,20%,3)
PW (p=0.22)=-6000+500*0.833333+1500*0.694444+2000*0.578704=-$3384.26
c)
Let us take the case, when probability=0.48
Initial Cash flow-Co=-$4000
Cash flow in year 1=CF1=$3100
Cash flow in year 2=CF2=$1200
Cash flow in year 3=CF3=$100
Interest rate=i=20%
PW (p=0.48)=-Co+CF1*(P/F,20%,1)+CF2*(P/F,20%,2)+CF3*(P/F,20%,3)
PW (p=0.48)=-4000+3100*0.833333+1200*0.694444+100*0.578704=-$525.46
d)
Expected present worth=0.30*(-2893.52)+0.22*(-3384.26)+0.48*(-525.46)=-$1864.81