In: Statistics and Probability
Set up and solve an LP model using Excel to crash this project to 24 days. What is the total crashing cost?
| 
 ACTIVITY  | 
 IMMEDIATE PREDECESSORS  | 
 STANDARD TIME (Days)  | 
 STANDARD COST  | 
 CRASH TIME (Days)  | 
 CRASH COST  | 
| 
 A  | 
 --  | 
 7  | 
 $2,000  | 
 5  | 
 $3,500  | 
| 
 B  | 
 A  | 
 10  | 
 $3,000  | 
 8  | 
 $4,700  | 
| 
 C  | 
 A  | 
 8  | 
 $3,400  | 
 7  | 
 $3,700  | 
| 
 D  | 
 C  | 
 6  | 
 $1,600  | 
 4  | 
 $2,600  | 
| 
 E  | 
 C  | 
 7  | 
 $1,900  | 
 4  | 
 $4,000  | 
| 
 F  | 
 D,E  | 
 5  | 
 $1,200  | 
 3  | 
 $2,800  | 
| 
 G  | 
 B,C  | 
 11  | 
 $8,200  | 
 8  | 
 $10,900  | 
| 
 H  | 
 F,G  | 
 4  | 
 $2,600  | 
 3  | 
 $3,800  | 
| Results | ||||||||||||
| Data | Normal time | 32 | Minimum crash cost to meet project goal | $ 9,700 | ||||||||
| Project goal | 24 | Minimum time | 24 | Project time | 24 | |||||||
| Immediate Predecessors (1 per column) | Intermediate Computations | |||||||||||
| Activity | Normal Time (weeks) | Crash Time (weeks) | Normal Cost | Total Cost with Crashing | Pred 1 | Pred 2 | Pred 3 | Pred 4 | Crash days | Crash cost/day | Crash limit | |
| A | 7 | 5 | $2,000 | $3,500 | 2 | 750 | 2 | |||||
| B | 10 | 8 | $3,000 | $4,700 | A | 2 | 850 | 2 | ||||
| C | 8 | 7 | $3,400 | $3,700 | A | 1 | 300 | 1 | ||||
| D | 6 | 4 | $1,600 | $2,600 | C | 0 | 500 | 2 | ||||
| E | 7 | 4 | $1,900 | $4,000 | C | 1 | 700 | 3 | ||||
| F | 5 | 3 | $1,200 | $2,800 | D | E | 2 | 800 | 2 | |||
| G | 11 | 8 | $8,200 | $10,900 | B | C | 3 | 900 | 3 | |||
| H | 4 | 3 | $ 2,600 | $ 3,800 | F | G | 1 | 1200 | 1 | |||
The total crashing cost is $9,700.