In: Statistics and Probability
Set up and solve an LP model using Excel to crash this project to 24 days. What is the total crashing cost?
ACTIVITY |
IMMEDIATE PREDECESSORS |
STANDARD TIME (Days) |
STANDARD COST |
CRASH TIME (Days) |
CRASH COST |
A |
-- |
7 |
$2,000 |
5 |
$3,500 |
B |
A |
10 |
$3,000 |
8 |
$4,700 |
C |
A |
8 |
$3,400 |
7 |
$3,700 |
D |
C |
6 |
$1,600 |
4 |
$2,600 |
E |
C |
7 |
$1,900 |
4 |
$4,000 |
F |
D,E |
5 |
$1,200 |
3 |
$2,800 |
G |
B,C |
11 |
$8,200 |
8 |
$10,900 |
H |
F,G |
4 |
$2,600 |
3 |
$3,800 |
Results | ||||||||||||
Data | Normal time | 32 | Minimum crash cost to meet project goal | $ 9,700 | ||||||||
Project goal | 24 | Minimum time | 24 | Project time | 24 | |||||||
Immediate Predecessors (1 per column) | Intermediate Computations | |||||||||||
Activity | Normal Time (weeks) | Crash Time (weeks) | Normal Cost | Total Cost with Crashing | Pred 1 | Pred 2 | Pred 3 | Pred 4 | Crash days | Crash cost/day | Crash limit | |
A | 7 | 5 | $2,000 | $3,500 | 2 | 750 | 2 | |||||
B | 10 | 8 | $3,000 | $4,700 | A | 2 | 850 | 2 | ||||
C | 8 | 7 | $3,400 | $3,700 | A | 1 | 300 | 1 | ||||
D | 6 | 4 | $1,600 | $2,600 | C | 0 | 500 | 2 | ||||
E | 7 | 4 | $1,900 | $4,000 | C | 1 | 700 | 3 | ||||
F | 5 | 3 | $1,200 | $2,800 | D | E | 2 | 800 | 2 | |||
G | 11 | 8 | $8,200 | $10,900 | B | C | 3 | 900 | 3 | |||
H | 4 | 3 | $ 2,600 | $ 3,800 | F | G | 1 | 1200 | 1 |
The total crashing cost is $9,700.