In: Finance
To answer the first question, let us assume that we have two bank savings a/c with deposit of $10000 in each bank namely AB Bank & XY Bank. Now also assume both the banks pay an interest rate of 12% per annum but in case of AB Bank, interest is compounded monthly whereas in case of XY Bank, the intersted is compunded annually.
Now as per formual, we know that, A = P[(1+r/n)^nt] where A= final amount payable by bank, P=Pricipal or amount deposited, r=rate of interest, n= number of times of compounding per year & t=number of year for which the money is invested.
In case of XY Bank where interest is compounded annually, A=10000[(1+0.12/1)^1*1] or, A=10000(1.12)^1 i.e. $11200.
Whereas in case of AB Bank where interst is compounded monthly, A=10000[(1+0.12/12)^1*12] or, A=10000(1.01)^12 i.e. $11268.25
So we will receive $68.25 more if the interest is compounded monthly when our investment amount and tenure of saving remain constant.
It is better to have a saving account where interest is compounded monthly rather than where interest is compunded annually for the fact that more the number of compounding more will be the interest earned.