In: Statistics and Probability
Solution :
Given that,
s2 = 18.49
2L
=
2
/2,df
= 42.980
2R
=
21 -
/2,df = 10.856
The 98% confidence interval for
is,
(n
- 1)s2 /
2
/2
<
<
(n - 1)s2 /
21 -
/2
24
* 18.49 / 42.980 <
<
24 * 18.49 / 10.856
3.21 <
< 6.39
(3.21 , 6.39)