In: Statistics and Probability
Solution :
Given that,
s2 = 18.49
2L = 2/2,df = 42.980
2R = 21 - /2,df = 10.856
The 98% confidence interval for is,
(n - 1)s2 / 2/2 < < (n - 1)s2 / 21 - /2
24 * 18.49 / 42.980 < < 24 * 18.49 / 10.856
3.21 < < 6.39
(3.21 , 6.39)