Question

In: Statistics and Probability

A random sample of 89 tourist in the Chattanooga showed that they spent an average of...

A random sample of 89 tourist in the Chattanooga showed that they spent an average of $2,860 (in a week) with a standard deviation of $126; and a sample of 64 tourists in Orlando showed that they spent an average of $2,935 (in a week) with a standard deviation of $138. We are interested in determining if there is any significant difference between the average expenditures of those who visited the two cities? a) Determine the degrees of freedom for this test. b) Compute the test statistic c) Compute the p-value(please show working of calculation) d) What is your conclusion?

Solutions

Expert Solution

Solution:

a) df= n1+n2-2= 89+64-2= 151

b)test statistic is:

c) p-value= 2*p(|t| < -3.49) = 2*0.0003= 0.0006

d) Conclusion:

P-value=0.0006 < 0.05, hence we reject Ho.

There is significant difference between two cities.


Related Solutions

1. At store A, the sample average amount spent by a random sample of 32 customers...
1. At store A, the sample average amount spent by a random sample of 32 customers was $31.22 with a sample standard deviation of $6.48. At store B, the sample average amount spent by a random sample of 36 customers was $34.68 with a sample standard deviation of $5.15. Test, using the 4-step procedure and a 5% level of significance, whether or not there is a difference between the population mean amount spent per customer at store A and the...
A random sample of 25 workers showed that the average workweek in the United States is...
A random sample of 25 workers showed that the average workweek in the United States is down to only 35 hours, largely because of a rise in part-time workers. The variance of the sample was 18.49 hours. Assuming that the population is normally distributed, calculate a 98% confidence interval for the population standard deviation.
A random sample of 81 cars traveling on a section of an interstate showed an average...
A random sample of 81 cars traveling on a section of an interstate showed an average speed of 68 mph. The distribution of speeds of all cars on this section of highway is normally distributed with a standard deviation of 10.5 mph. The 94.52 confidence interval for μ is from _____ to ____?
A random sample of 81 credit sales in a department store showed an average sale of...
A random sample of 81 credit sales in a department store showed an average sale of $68.00. From past data, it is known that the standard deviation of the population is $27.00. What is the 99% confidence interval of the population mean? (Round to two decimal places)
A random sample of 144 checking accounts at a bank showed an average daily balance of...
A random sample of 144 checking accounts at a bank showed an average daily balance of $395. The standard deviation of the population is known to be $72. Please answer the following questions: (a) Find the standard error of the mean. (b) Give a point estimate of the population mean. (c) Construct a 95% confidence interval estimates for the mean.
A random sample of 51 adult coyotes in a region of northern Minnesota showed the average...
A random sample of 51 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.05 years, with sample standard deviation s = 0.86 years. However, it is thought that the overall population mean age of coyotes is μ = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use α = 0.01. (a) What is the level of...
A random sample of 41 adult coyotes in a region of northern Minnesota showed the average...
A random sample of 41 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.09 years, with sample standard deviation s = 0.88 years. However, it is thought that the overall population mean age of coyotes is ? = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use ? = 0.01. (a) What is the level of...
A random sample of 5 months in an urban area showed an average of 28 mail...
A random sample of 5 months in an urban area showed an average of 28 mail carriers were bitten by dogs. If the population is normal and the standard deviation of the sample is 3 find the 95% confidence interval for the population mean.
A random sample of 20 students at a university showed an average age of 21.4 years...
A random sample of 20 students at a university showed an average age of 21.4 years and a sample standard deviation of 2.6 years. The 98% confidence interval for the true average age of all students in the university is? Enter in the upper limit of your confidence interval
-A random sample of 15 checking accounts at a bank showed an average balance of $280....
-A random sample of 15 checking accounts at a bank showed an average balance of $280. The standard deviation of the sample was $60. Construct a 90% confidence interval for the mean and explain what it shows you in the context of the problem. Show your work and show your calcualtor steps. -A local health center noted that in a sample of 400 patients 80 were referred to them by the local hospital. Provide a 95% confidence interval for the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT