Question

In: Statistics and Probability

A) A study of elephants wishes to determine the average weight of a certain subspecies of...

A) A study of elephants wishes to determine the average weight of a certain subspecies of elephants. The standard deviation of the population is 500 pounds. How many elephants need to be weighed so that we can be 95% confident to be accurate within 200 pounds?

B) TRUE OR FALSE: The confidence level of an interval estimate of a parameter is the probability that the interval estimate is one that will contain the parameter.

C) A report states that 42% of home owners had a vegetable garden. How large a sample is needed to estimate the true proportion of home owners who have vegetable gardens to within 6% with 95% confidence?

Solutions

Expert Solution

Refer Z-table or use excel function "=NORM.S.INV((1-0.025))" to find the Z-value.

-----------------------------------------------------------------------------------------------------------------------------

The confidence level is expressed as a percentage or a probability, that a specified interval will contain the population parameter.

-----------------------------------------------------------------------------------------------------------------------------

Refer Z-table or use excel function "=NORM.S.INV((1-0.025))" to find the Z-value.


Related Solutions

1. A producer of infant formula wishes to study how the average weight Y (in kilograms)...
1. A producer of infant formula wishes to study how the average weight Y (in kilograms) of children changes during the first year of life. He plots these averages versus the age X (in months) and decides to fit a least-squares regression line to the data with X as the explanatory variable and Y as the response variable. He computes the following quantities: r = 0.9   = 2.5   = 8       = 1.2   = 3.6 a. Calculate the regression equation...
In an obesity study, a researcher wishes to determine if age, average sleep duration, and depression...
In an obesity study, a researcher wishes to determine if age, average sleep duration, and depression score have any effect on a person’s weight. The researcher takes a random sample of 25 participants that have been diagnosed as obese and records their measurements. Using the data, create the regression output (not including the y-intercept) then answer the questions below. Note that all variables are quantitative. Let α = 0.05. Write out the estimated regression line. To receive full credit, you...
A sample of 7 adult elephants had an average weight of 11900 pounds. The standard deviation...
A sample of 7 adult elephants had an average weight of 11900 pounds. The standard deviation for the sample was 24 pounds. What is the 99% confidence interval of the population mean for the weights of adult elephants? Assume that the variable is normally distributed.
A sample of 9 adult elephants has an average weight of 12,500 pounds. The standard deviation...
A sample of 9 adult elephants has an average weight of 12,500 pounds. The standard deviation for the sample was 24 pounds. Find the 99% confidence interval of the population mean for the weight of adult elephants. Assume the variable is normally distributed. Round answer to the nearest whole number.
researcher wishes to test the claim that the average weight of an adult elephant is 12500...
researcher wishes to test the claim that the average weight of an adult elephant is 12500 pounds. The researcher collected a sample of 33 adult elephants. The sample average for the weight of the elephants was 12200 pounds. The population standard deviation is believed to be 720 pounds. With alpha = 0.06, is there enough evidence to reject the claim. a) Is this a test that uses, z-scores, t-scores, or chi-squared values? b) [2 points] Does this problem involve proportions?...
Boys of a certain age in the nation have an average weight of 86 with a...
Boys of a certain age in the nation have an average weight of 86 with a standard deviation of 10.5 lb. A complaint is made that boys are overfed fed in a municipal children's home. As evidence, a sample of 19 boys of the given age is taken from the children's home with an average weight of 79.52 lb. What can be concluded with α = 0.05? a) What is the appropriate test statistic? ---Select--- na z-test one-sample t-test independent-samples...
Children of a certain age in the nation have an average weight of 85 with a...
Children of a certain age in the nation have an average weight of 85 with a standard deviation of 9.5 lb. A complaint is made that children are improperly fed in a boarding school. As evidence, a sample of 14 children of the given age is taken from the boarding school with an average weight of 89.44 lb. What can be concluded with an α of 0.05? a) What is the appropriate test statistic? -na z test one sample t...
Boys of a certain age in the nation have an average weight of 85 with a...
Boys of a certain age in the nation have an average weight of 85 with a variance of 114.49 lb. A complaint is made that boys are overfed in a municipal children's home. As evidence, a sample of 21 boys of the given age is taken from the children's home with an average weight of 92.5 lb. What can be concluded with α = 0.05? a) What is the appropriate test statistic? ---Select--- na z-test One-Sample t-test Independent-Samples t-test Related-Samples...
The time it takes a randomly selected rat of a certain subspecies to find its way...
The time it takes a randomly selected rat of a certain subspecies to find its way through a maze is normally distributed with µ = 1.5 minutes and σ = 0.35 minutes. Suppose 30 rats are selected. Let X1,X2,...,X30 denote their times in the maze. (a) What are the mean and standard deviation for total time for all 30 rats in the maze? (b) What is the probability that the total time for the 30 rats is between 45 and...
A doctor wishes to determine which of two diets is more effective in reducing weight. A...
A doctor wishes to determine which of two diets is more effective in reducing weight. A sample of 20 obese adults who are interested in losing weight is randomly divided into groups of 10. After 6 weeks the weight loss of each participant was recorded. The mean for diet 1 is 8 pounds with a standard deviation of 3.23 pounds. The mean for diet 2 is 11 pounds with a standard deviation of 6.78 pounds. Does the data justify the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT