In: Statistics and Probability
A process engineer developed a new packaging technique for coffee bags which is believed to provide a standard deviation for the weight of coffee in the bag equal to 5g. A sample of 25 coffee bags is found to have a standard deviation of 7g.
a) Yes (P-value<0.025) b)Yes (P-value>0.05) c)Yes (P-value<0.05) d)Yes (P-value>0.025)
e) No (P-value<0.025) f)No (P-value>0.05) g)No (P-value<0.05) h)No (P-value>0.025)
A sample of 25 bags of coffee packed according to the traditional method provides a standard deviation of the coffee weight equal to 9.5g. Recall that a sample of 25 bags packed with the new packaging technique provides a standard deviation of 7g.
a) Yes (P-value<0.025) b)Yes (P-value>0.05) c)Yes (P-value<0.05) d)Yes (P-value>0.025)
e) No (P-value<0.025) f)No (P-value>0.05) g)No (P-value<0.05) h)No (P-value>0.025)
According to a recent survey, during the Thanksgiving dinner, 65% of Americans prefer to deep fry the turkey rather than baking it into the oven. From a random sample of 30 American families, we find that only 16 of them fried the turkey on Thanksgiving.
a) Yes (P-value<0.025) b)Yes (P-value>0.05) c)Yes (P-value<0.05) d)Yes (P-value>0.025)
e) No (P-value<0.025) f)No (P-value>0.05) g)No (P-value<0.05) h)No (P-value>0.025)
Answer: A process engineer developed a new packaging technique for coffee bags which is believed to provide a standard deviation for the weight of coffee in the bag equal to 5g. A sample of 25 coffee bags is found to have a standard deviation of 7g.
Solution:
Answer: A sample of 25 bags of coffee packed according to the traditional method provides a standard deviation of the coffee weight equal to 9.5g. Recall that a sample of 25 bags packed with the new packaging technique provides a standard deviation of 7g.
Solution:
According to a recent survey, during the Thanksgiving dinner, 65% of Americans prefer to deep fry the turkey rather than baking it into the oven. From a random sample of 30 American families, we find that only 16 of them fried the turkey on Thanksgiving.
Solution:
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