Question

In: Statistics and Probability

A researcher randomly divides 19 subjects into two groups. One group receives a new drug called...

A researcher randomly divides 19 subjects into two groups. One group receives a new drug called RT56 for 3 months, the other a placebo (looks like RT56, but is a sugar pill). She then measures reaction time (RT) on a complex task and finds the following RT s in seconds (s): Group 1 Group 2 RT56 Placebo N=10 N=9 .456 .532 .347 .458 .435 .768 .234 .643 .521 .678 .411 .569 .398 .486 .254 .647 .391 .501 .289

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Result:

A researcher randomly divides 19 subjects into two groups. One group receives a new drug called RT56 for 3 months, the other a placebo (looks like RT56, but is a sugar pill). She then measures reaction time (RT) on a complex task and finds the following RT s in seconds (s): Group 1 Group 2 RT56 Placebo N=10 N=9 .456 .532 .347 .458 .435 .768 .234 .643 .521 .678 .411 .569 .398 .486 .254 .647 .391 .501 .289

independent variable: treatment( RT56 and Placebo) and dependent variables: reaction time

Null Hypothesis in words and symbols.
  

Ho: There is no difference in average reaction time between RT56 and Placebo groups

H1: There is a difference in average reaction time between RT56 and Placebo groups

Ho: µ1 = µ2   H1: µ1 ≠ µ2

Compute the appropriate statistic.
  

Pooled-Variance t Test for the Difference Between Two Means

(assumes equal population variances)

Data

Hypothesized Difference

0

Level of Significance

0.05

Population 1 Sample

Sample Size

10

Sample Mean

0.3736

Sample Standard Deviation

0.0920

Population 2 Sample

Sample Size

9

Sample Mean

0.5869

Sample Standard Deviation

0.1033

Intermediate Calculations

Population 1 Sample Degrees of Freedom

9

Population 2 Sample Degrees of Freedom

8

Total Degrees of Freedom

17

Pooled Variance

0.0095

Standard Error

0.0448

Difference in Sample Means

-0.2133

t Test Statistic

-4.7611

Two-Tail Test

Lower Critical Value

-2.1098

Upper Critical Value

2.1098

p-Value

0.0002

Reject the null hypothesis

Calculated t= -4.7611

DF = n1+n2-2 =17

Table value of t with 17 DF at 0.05 level = 2.1098

Rejection Region: Reject Ho if t < -2.1098 or t > 2.1098

Calculated t = -4.7611 in the rejection region

The null hypothesis is rejected.

There is enough evidence in the data to conclude that there is a difference in average reaction time between RT56 and Placebo groups.


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