In: Statistics and Probability
A researcher randomly divides 19 subjects into two groups. One group receives a new drug called RT56 for 3 months, the other a placebo (looks like RT56, but is a sugar pill). She then measures reaction time (RT) on a complex task and finds the following RT s in seconds (s): Group 1 Group 2 RT56 Placebo N=10 N=9 .456 .532 .347 .458 .435 .768 .234 .643 .521 .678 .411 .569 .398 .486 .254 .647 .391 .501 .289
Result:
A researcher randomly divides 19 subjects into two groups. One group receives a new drug called RT56 for 3 months, the other a placebo (looks like RT56, but is a sugar pill). She then measures reaction time (RT) on a complex task and finds the following RT s in seconds (s): Group 1 Group 2 RT56 Placebo N=10 N=9 .456 .532 .347 .458 .435 .768 .234 .643 .521 .678 .411 .569 .398 .486 .254 .647 .391 .501 .289
independent variable: treatment( RT56 and Placebo) and dependent variables: reaction time
Null Hypothesis in words and symbols.
Ho: There is no difference in average reaction time between RT56 and Placebo groups
H1: There is a difference in average reaction time between RT56 and Placebo groups
Ho: µ1 = µ2 H1: µ1 ≠ µ2
Compute the appropriate statistic.

|
Pooled-Variance t Test for the Difference Between Two Means |
|
|
(assumes equal population variances) |
|
|
Data |
|
|
Hypothesized Difference |
0 |
|
Level of Significance |
0.05 |
|
Population 1 Sample |
|
|
Sample Size |
10 |
|
Sample Mean |
0.3736 |
|
Sample Standard Deviation |
0.0920 |
|
Population 2 Sample |
|
|
Sample Size |
9 |
|
Sample Mean |
0.5869 |
|
Sample Standard Deviation |
0.1033 |
|
Intermediate Calculations |
|
|
Population 1 Sample Degrees of Freedom |
9 |
|
Population 2 Sample Degrees of Freedom |
8 |
|
Total Degrees of Freedom |
17 |
|
Pooled Variance |
0.0095 |
|
Standard Error |
0.0448 |
|
Difference in Sample Means |
-0.2133 |
|
t Test Statistic |
-4.7611 |
|
Two-Tail Test |
|
|
Lower Critical Value |
-2.1098 |
|
Upper Critical Value |
2.1098 |
|
p-Value |
0.0002 |
|
Reject the null hypothesis |
Calculated t= -4.7611
DF = n1+n2-2 =17
Table value of t with 17 DF at 0.05 level = 2.1098
Rejection Region: Reject Ho if t < -2.1098 or t > 2.1098
Calculated t = -4.7611 in the rejection region
The null hypothesis is rejected.
There is enough evidence in the data to conclude that there is a difference in average reaction time between RT56 and Placebo groups.