Question

In: Physics

A copper calorimeter can with mass 0.555kg contains 0.165kg of water and 1.90

Expert Solution

GIven

mass of copper calorimeter m_cu = 0.555 kg

specific heat of copper calorimeter c_cu = 390 J / kg . K

mass of water m _w = 0.165 kg

specific heat of water c_w = 4190 J / kg . K

mace of ice m _i = 0.019 kg

latent heat of ice = 334*10³ J / kg

mass of lead m_pb = 0.755 kg

specific heat of lead c_pb = 130 J / kg . K

Heat lost by the lead is

Q = m _pb c _pb ( 255- T )

= 0.755 * 130 J / kg . K *(255- T )

= 98.15 ( 255-T )

heat gained by calorimeter

Q = ( m_w + m _ice) c_w T + m _cu c_cu T +m_ice L _f

= ( 0.165+0.019)(4190) T + (0.555)(390 J / kg . k ) T + (0.019 kg )(334*10³ )

heat loss by lead is equal to heat gained by calorie meter

98.15 ( 255-T ) = 770.96 T + 216.45 T + 6346

18682.25 = 1085.56 T

T = 17.21 ^o C --> Answer

genius_generous answered 1 year ago

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