In: Statistics and Probability
Let x be a random variable that represents the level of glucose in the blood (milligrams per deciliter of blood) after a 12-hour fast. Assume that for people under 50 years old, x has a distribution that is approximately normal, with mean μ = 55 and estimated standard deviation σ = 41. A test result x < 40 is an indication of severe excess insulin, and medication is usually prescribed.
(a) What is the probability that, on a single test, x
< 40? (Round your answer to four decimal places.)
(b) Suppose a doctor uses the average x for two tests
taken about a week apart. What can we say about the probability
distribution of x? Hint: See Theorem 7.1.
The probability distribution of x is not normal.The probability distribution of x is approximately normal with μx = 55 and σx = 41. The probability distribution of x is approximately normal with μx = 55 and σx = 28.99.The probability distribution of x is approximately normal with μx = 55 and σx = 20.50.
What is the probability that x < 40? (Round your answer
to four decimal places.)
(c) Repeat part (b) for n = 3 tests taken a week apart.
(Round your answer to four decimal places.)
(d) Repeat part (b) for n = 5 tests taken a week apart.
(Round your answer to four decimal places.)
Solution :
Given that ,
mean = = 55
standard deviation = = 41
a) P(x < 40) = P[(x - ) / < (40 - 55) / 41]
= P(z < -0.37)
Using z table,
= 0.3557
b) n = 2
= = 55
= / n = 41/ 2 = 28.99
The probability distribution of x is approximately normal with μx = 55 and σx = 28.99.
P( < 40) = P(( - ) / < (40 - 55) / 28.99)
= P(z < -0.52)
Using z table
= 0.3015
c) n = 3
= = 55
= / n = 41/ 3 = 23.67
The probability distribution of x is approximately normal with μx = 55 and σx = 23.67
P( < 40) = P(( - ) / < (40 - 55) / 23.67)
= P(z < -0.63)
Using z table
= 0.2643
d) n = 5
= = 55
= / n = 41/ 5 = 18.34
The probability distribution of x is approximately normal with μx = 51 and σx = 18.34
P( < 40) = P(( - ) / < (40 - 55) / 18.34)
= P(z < -0.82)
Using z table
= 0.2061