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Python ONLY ONE STATEMENT ALLOWED PER FUNCTION (ONE RETURN STATEMENT ALLOWED) def plsfollowrule(num): return num like...

Python

ONLY ONE STATEMENT ALLOWED PER FUNCTION (ONE RETURN STATEMENT ALLOWED)
def plsfollowrule(num):

return num

like this.

1) create a function popular. The dictionary called database contains each people's hobby and their excitement level. This function searches the dictionary and returns a list of that most popular hobby to least popular hobby. If multiple hobbies have the same number of popularity, follow alphabetical order.

#What is popular means? The dictionary contains each people's hobby. The programmer should search the dictionary and figure out how many times this hobby popular to the people.

For example

database = {'Dio': {'Lottery': 2, 'Chess': 4, 'Game': 3},'Baily': {'Game': 2, 'Tube': 1, 'Chess': 3}, 'Chico': {'Punch': 2, 'Chess': 5}, 'Aaron': {'Chess': 4, 'Tube': 2, 'Baseball': 1}}

def popular(database) -> list:

#ONE STATEMENT ALLOWED, THAT WILL BE ONE RETURN STATEMENT

output

['Chess', 'Game', 'Tube', 'Baseball', 'Lottery', 'Punch']

#Chess appear the most time which 4

#Game appear 2 times

#Tube appear 2 times but by the alphabetical order, it located after game

#baseball appear 1 time

#lottery appear 1 time but by the alphabetical order, it located after baseball

#punch appear 1 time but by the alphabetical order, it located after lottery

Solutions

Expert Solution

from collections import Counter,OrderedDict
from operator import itemgetter

# function to return list of most popular to least popular hobby
def popular(database):
    return list(OrderedDict(sorted(OrderedDict(Counter(sorted([b for a in database.values() for b in a]))).items(), key=itemgetter(1,1), reverse=True)).keys())


# dictionary contains each people's hobby with excitement level
database = {'Dio': {'Lottery': 2, 'Chess': 4, 'Game': 3},'Baily': {'Game': 2, 'Tube': 1, 'Chess': 3},
            'Chico': {'Punch': 2, 'Chess': 5}, 'Aaron': {'Chess': 4, 'Tube': 2, 'Baseball': 1}}
print(popular(database))

venereology answered 1 year ago
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