Question

In: Statistics and Probability

A two-way table is given below, which shows the counts of the favorite leisure activities for...

A two-way table is given below, which shows the counts of the favorite leisure activities for 50 college students - 20 men and 30 women. Leisure Activity Yoga Sports TV Total Men 2 10 8 20 Women 16 6 8 30 Total 18 16 16 50 (a) What is the probability that a student selected at random is both a woman and student prefers Yoga? (b) What is the probability that a student is either a male or prefers sports? (c) What is the probability that a student selected at random prefers to watch television? (d) What is the probability that a female student selected at random, prefers television? (e) Draw the tree diagram for the above table. Be sure to label all probabilities.

Expert Solution

activity	yoga	sports	tv	total
men	2	10	8	20
woman	16	6	8	30

a)Probability(woman and prefers yoga)=16/50=0.32

b)total men=20

total no. of students playing sports=16

no. of men playing sports=10

probability(either male or plays sports)= P(A)+P(B)-P(A and B)= 20/50+16/50-10/50= 0.52

c)total no. of students watching tv= 8+8=16

probability(students watching tv)= 16/50=0.32

d)Probability(female student watches tv)=8/30=0.27

e)each probability of the event occuring is in front of the arrow of the event

0.1

0.4 0.5

0.4

0.53

0.60.2

0.27

orchestra answered 2 years ago

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