In: Statistics and Probability
A manufacturer knows that their items have a normally
distributed length, with a mean of 18 inches, and standard
deviation of 4.2 inches.
If 20 items are chosen at random, what is the probability that
their mean length is less than 15.5 inches? (Give answer to 4
decimal places.)
A manufacturer knows that their items have a normally
distributed length, with a mean of 6.4 inches, and standard
deviation of 1.2 inches.
If 10 items are chosen at random, what is the probability that
their mean length is less than 5.4 inches? (Give answer to 4
decimal places.)
Solution :
1) Given that ,
= 18
= / n = 4.2/ 20 = 0.939
P( < 15.5 ) = P(( - ) / < (15.5 - 18) / 0.939)
= P(z < -2.66 )
Using z table
= 0.0039
2) Given that ,
= 6.4
= / n = 1.2/ 10 = 0.379
P( < 5.4 ) = P(( - ) / < (5.4 - 6.4) / 0.379)
= P(z < -2.64 )
Using z table
= 0.0041