Question

An initial concentration of CO₂ equal to 1.00 M is in a flask at 25°. What is the equilibrium concentration of CO₂? The K_c is 3.2 ´ 10^-3 at 25°C. SnO2(s) + 2 CO(g)   D   Sn(s) + 2 CO2(g) Hrxn = –36 kJ

Answer 1

SnO2 (s)   + 2 CO (g)   ---------------> Sn (s) + 2 CO2 (g)

                   0                                                1.00 M

                      2x                                                1 - 2x

Kc = (1-2x)^2 / (2x)^2

3.2 x 10^-3 = (1-2x)^2 / (2x)^2

1-2x / 2x = 0.0566

1 - 2x = 0.113 x

x = 0.473

equilibrium concentration of CO₂ = 1 - 2x

equilibrium concentration of CO2   = 0.0535 M