In: Chemistry
A 1.00 L flask is filled with 1.45 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pressure is 1.450 atm .
What is the partial pressure of ethane, Pethane, in the flask? Express your answer to three significant figures and include the appropriate units.
A:- From the ideal gas equation, PV = nRT we have to solve this problem as,
=> Partial pressure of argon, Pargon = nRT / V
= ((1.45 g Ar) / (39.9480 g Ar/mol)) x (0.08206 L atm/K mol) x (25
+ 273.15)K / (1.00 L)
Partial pressure of argon, Pargon =0.888 atm
=> Partial pressure of ethane, Pethane =
Ptotal - Pargon
= (1.450 - 0.888)
Pethane = 0.562 atm