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In: Chemistry

A 1.00 L flask is filled with 1.45 g of argon at 25 ∘C. A sample...

A 1.00 L flask is filled with 1.45 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pressure is 1.450 atm .

What is the partial pressure of ethane, Pethane, in the flask? Express your answer to three significant figures and include the appropriate units.

Solutions

Expert Solution

A:- From the ideal gas equation, PV = nRT we have to solve this problem as,

=> Partial pressure of argon, Pargon = nRT / V

                                        = ((1.45 g Ar) / (39.9480 g Ar/mol)) x (0.08206 L atm/K mol) x (25 + 273.15)K / (1.00 L)
Partial pressure of argon, Pargon =0.888 atm

=> Partial pressure of ethane, Pethane = Ptotal - Pargon

                                                   = (1.450 - 0.888)

                                            Pethane = 0.562 atm

queen_honey_blossom answered 2 years ago
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