Here is the equation 2 C 4 H 10 (g)+13 O 2 (g)→10 H 2 O(g)+8C...

Here is the equation 2 C 4 H 10 (g)+13 O 2 (g)→10 H 2 O(g)+8C O 2 (g) Calculate the mass of water produced when 1.20 g of butane reacts with excess oxygen. Calculate the mass of butane needed to produce 68.0 g of carbon dioxide.

Expert Solution

1)

2 C4H10 + 13 O2 ------------------------> 10 H2O + 8 CO2

116 g 180 g

1.20 g ?

mass of water produced = 180 x 1.20 / 116

= 1.86 g

mass of water produced = 1.86 g

2)

2 C4H10 + 13 O2 ------------------------> 10 H2O + 8 CO2

116 g 352 g

? 68.0 g

mass of butane = 116 x 68 / 352

= 22.4 g

mass of butane = 22.4 g

queen_honey_blossom answered 2 years ago

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