In: Chemistry
Fill in the blanks to complete the following table.
Symbol | Ion Formed | Number of Electrons in Ion | Number of Protons in Ion |
F | _____ | _____ | 9 |
Te | _____ | 54 | _____ |
I | I− | _____ | _____ |
_____ | Mg2+ | _____ | 12 |
Part A
Complete the first column of the table.
Express your answer as a chemical symbol.
Part B
Complete the second column of the table.
Express your answer as ions. Enter your answers in order given in the table, from top to bottom, separated by a comma.
Part C
Complete the third column of the table.
Express your answer as integers. Enter your answers in order given in the table, from top to bottom, separated by commas.
electrons
Part D
Complete the fourth column of the table.
Express your answer as integers. Enter your answers in order given in the table, from top to bottom, separated by a comma.
Symbol | Ion Formed | Number of Electrons in Ion | Number of protons in Ion |
F | F- | 10 | 9 |
Te | Te4+ | 48 | 52 |
I | I- | 54 | 53 |
Mg | Mg2+ | 10 | 12 |
Explanation :-
Symbol of the atom is : ZXA
A = Atomic mass and Z = Atomic number
Number of protons (p) = Atomic number (Z)
Number of electrons (e) = Number of protons (p) for neutral atom
(a). The most common oxidation state of F is -1, therefore F ion is : F-
Symbol = 9F19 , Number of protons = 9 , Number of electrons in F- = 9 + 1= 10
(b). The most common oxidation state of Te is +4, therefore Te ion is : Te4+
Symbol = 52Te127.6 , Number of p = 52 , Number of electrons in Te4+ = 52-4 = 48
(c). The most common oxidation state of I is -1, therefore I ion is : I-
Symbol =53I126.9 , Number of protons = 53 , Number of electrons in I- = 53 + 1= 54
(d). The most common oxidation state of Mg is +2, therefore Mg ion is : Mg2+
Symbol = 12Mg24 , Number of protons = 12 , Number of electrons in Mg2+ = 12-2 = 10