In: Finance
Question 1
Suppose you work for a major steel producer in Northwest Indiana and oversee decisions about maintenance and repairs of manufacturing equipment. One day, your team informs you that they have discovered that an important machine is on track to fail in exactly three years. You are then faced with three options:
Option 1: Do
nothing.
You can do nothing, and the machine will fail three years from now
causing damage to other components when it fails. Replacing the
machine and the other damaged components at that time will cost
$1,000,000.
Option 2: Perform
temporary repairs.
You can complete some temporary repairs, which will cost you
$200,000 right now and the machine will still fail in three years,
but then when it fails it won’t damage other components and
replacing the machine at that time will cost you $750,000.
Option 3: Replace
the machine now.
You can replace the machine right now rather than waiting for it to
fail in three years, which will cost $850,000 now.
For all three options assume that everything else will be identical after these three years (i.e. you will have a machine that works perfectly fine) and that there are no other costs that have not been mentioned. Considering these three options, answer the following questions:
Qx | Px | Py | Pz | A |
524 | 3.21 | 4.68 | 4.56 | 4604 |
398 | 7.25 | 7.26 | 7.53 | 2844 |
493 | 5.09 | 5.3 | 5.54 | 3996 |
564 | 5.33 | 1.98 | 0.65 | 5713 |
544 | 4.49 | 4.82 | 4.73 | 5084 |
441 | 3.59 | 4.2 | 4.5 | 3173 |
362 | 4.41 | 3.39 | 1.94 | 1728 |
442 | 5.28 | 2.29 | 2.4 | 3719 |
512 | 5.03 | 4.25 | 4.04 | 4781 |
423 | 3.01 | 0.86 | 1.53 | 2791 |
Qx | Px | Py | A |
524 | 3.21 | 4.68 | 4604 |
398 | 7.25 | 7.26 | 2844 |
493 | 5.09 | 5.3 | 3996 |
564 | 5.33 | 1.98 | 5713 |
544 | 4.49 | 4.82 | 5084 |
441 | 3.59 | 4.2 | 3173 |
362 | 4.41 | 3.39 | 1728 |
442 | 5.28 | 2.29 | 3719 |
512 | 5.03 | 4.25 | 4781 |
423 | 3.01 | 0.86 | 2791 |
Present Value = Future Value/(1 + Interest Rate)n
where n = number of years
4) When the interest rate is 4%, then the best and most
cost-effective option for repair is Option 3
When the interest rate is 7%, then the best and most cost-effective
option for repair is Option 2
When the interest rate is 10%, then the best and most
cost-effective option for repair is Option 1
We can see that as and when the interest rate increase, the
present value reduces. In other words, you will have to save less
today if you have a higher interest rate because of the compounding
effect.
From a worker's safety point of view, option 1 is the most
dangerous one as it will do more harm in a later stages if no
action is taken today.