In: Statistics and Probability
| 
 Therapy A  | 
 Therapy B  | 
 Therapy C  | 
| 
 5  | 
 3  | 
 5  | 
| 
 2  | 
 2  | 
 4  | 
| 
 3  | 
 3  | 
 3  | 
| 
 1  | 
 1  | 
 6  | 
| 
 4  | 
 4  | 
 5  | 
| 
 4  | 
 5  | 
 6  | 
| 
 3  | 
 3  | 
 7  | 
| 
 0  | 
 2  | 
 4  | 
| 
 2  | 
 2  | 
 7  | 
| 
 4  | 
 1  | 
 5  | 
Contrast Hypothesis 1: μTherapyA ≠ μTherapyC
Assume now that the clinical psychologist had no a priori hypotheses about the nature of any differences. Instead, the researcher wants to compute all possible pairwise comparisons post-hoc. Use SPSS to compute all possible pairwise comparisons. What are your results? What do you conclude?
From the given data, the following Table is calculated:
| Therapy A | Therapy B | Therapy C | Total | |
| N | 10 | 10 | 10 | 30 | 
![]()  | 
28 | 26 | 52 | 106 | 
| Mean | 2.8 | 2.6 | 5.2 | 3.533 | 
![]()  | 
100 | 82 | 286 | 468 | 
| Std. Dev. | 1.5492 | 1.2649 | 1.3166 | 1.7953 | 
From the above Table, ANOVA Table is Calculated as follows:
| Source of variation | Sum of Squares | Degrees of freedom | Mean Square | F | 
| Between Treatments | 41.8667 | 2 | 20.9333 | 10.9535 | 
| Within treatments | 51.6 | 27 | 1.9111 | |
| Total | 93.4667 | 29 | 
The F - Ratio = 10.9535. The p - value =0.0003. The result is significant at p <0.05
Question (a)
State
your hypotheses:
H0 : Null Hypothesis: 
HA: Alternative Hypothesis: 
 (At least one mean is different
from other 2 means)
Question (b):
Determine the characteristic of the comparison distribution:
F Distribution with Degrees of Freedom for numerator = 2 and Degrees of Freedom for denominator = 27
Question C:
Determine the cut off value for a 5% significance level:
From Table, critical value of F is given by:
3.354

As per the guideline i have solve first 5 Qs, kindly share other Qs individually. Thanks